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3 years ago

3 times the sum of 1/3 of a number and 8 is 11

1 answer:

8 0

Let the number be x.

1/3 of the number = (1/3)*x = x/3

Sum of it and 8 = (x/3) + 8

3 times the sum = 3*((x/3) + 8) = 11

3*((x/3) + 8) = 11

3*x/3 + 3*8 = 11

x + 24 = 11

x = 11 - 24

x = -13

The number is - 13.

I hope this helps.

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(7p+8)-(5p-2) combine like terms

kotegsom [21]

The answer is:

= 2p+10

8 0

3 years ago

Reduce fraction: a^3+a^2b/5a times 25/3b+3a

Margaret [11]

ANSWER

$\frac{5a}{3}$

EXPLANATION

The given fractions are:

$\frac{{a}^{3} + {a}^{2} b}{5a} \times \frac{25}{3b + 3a}$

We factor to obtain:

$\frac{{a}^{2}(a + b)}{5a} \times \frac{25}{3(a + b)}$

We cancel the common factors to get:

$\frac{{a}(1)}{1} \times \frac{5}{3(1)}$

We multiply the numerators and also multiply the denominators to get:

$\frac{5a}{3}$

Therefore the two fractions simplifies to $\frac{5a}{3}$

3 0

3 years ago

Line.

Tasya [4]

Answer:

Simpson

Step-by-step explanation:

4 0

2 years ago

Graph f(x)=2x+1 and g(x)=−x+7 on the same coordinate plane.

Tamiku [17]

Answer:

x = 2

Step-by-step explanation:

To solve the equation, you need to set both functions equal to each other and simplify to find the value of "x".

f(x) = 2x + 1

g(x) = -x + 7

f(x) = g(x) <----- Given equation

2x + 1 = -x + 7 <----- Insert functions

3x + 1 = 7 <----- Add "x" to both sides

3x = 6 <----- Subtract 1 from both sides

x = 2 <----- Divide both sides by 3

8 0

1 year ago

three friends are in the same algebra class. Their scores on a recent test are three consecutive odd intergers whose sum is 279.

jasenka [17]

X= 1st integer
x+2= 2nd integer
x+4= 3rd integer

Add the integers together

x + (x + 2) + (x + 4)= 279
combine like terms
3x + 6= 279
subtract 6 from both sides
3x= 273
divide both sides by 3
x= 91 first integer

Substitute x=91 to find 2nd & 3rd integers

2nd Integer
=x+2
=91+2
=93

3rd Integer
=x+4
=91+4
=95

ANSWER: The three test scores are 91, 93 and 95.

Hope this helps! :)

7 0

2 years ago