30 M&Ms
1) Gathering the data
12-ounce bag of trail mix = 18 M&Ms
20-ounce bag=?
2) Assuming that the M&Ms are placed in following a constant rate we can write the following proportion:
12 --------------- 18
20 --------------- y
<em>Cross multiplying it due to the first property of proportions</em>
<em />
12y =20 x 18
12y = 360
y=30
3) So, I'd expect to find 30 M&Ms at a 20-ounce bag of trail mix.
I am so sorry but I can’t see the question because if the glare on it
The answer is ae=12 that what i got right on my test
Answer: 44.7
Step-by-step explanation:
Mean= total sum of data set/ number of data set
313÷7
Mean = 44.7
Here is the solution of the given problem above.
Given: Weight of single calf = weight of mother + 3.8%
Weight of mother = 3.75 tons or 7,500 pounds
? = weight of the calf
First, we need to find the 3.8% of 7,500 pounds. The result is 285 pounds.
So to get the weight of the calf, let's add 7,500 pounds to 285 pounds and the result is 7,785 pounds. So the weight of the calf is 7,785 pounds. Hope this helps.
