Answer:
x= 2/3 = 0.667
Step-by-step explanation:
<h2>
Hello!</h2>
The answers are:

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Why?</h2>
Since we are given the margin of error and it's equal to ±0.1 feet, and we know the surveyed distance, we can calculate the maximum and minimum distance. We must remember that margin of errors usually involves and maximum and minimum margin of a measure, and it means that the real measure will not be greater or less than the values located at the margins.
We know that the surveyed distance is 1200 feet with a margin of error of ±0.1 feet, so, we can calculate the maximum and minimum distances that the reader could assume in the following way:


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Answer:
x = √(3^125/ 5)
approx 2.9552445 * 10^29.
Step-by-step explanation:
2 log3 x + log3 5 =125
log3 x^2 + log3 5 = 125
log3 (5x^2) = 125
3^125 = 5x^2
x^2 = 3^125/ 5
x = √(3^125/ 5)
This is a huge number
An approximation of it is 2.9552445 * 10^29.
Answer: g = 10
Step-by-step explanation: 8g + 3 = –6g + 13g + 13
8g + 3 = (–6g + 13g) + (13)
8g + 3 = 7g + 13
8g + 3 - 7g = 7g + 13 - 7g
g + 3 = 13
g + 3 - 3 = 13 - 3
g = 10