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9966 [12]
3 years ago
12

a snail moved 1/6 foot in 1/2 hour find the speed of the snail in feet per hour write ancer in simpelest form

Mathematics
2 answers:
Makovka662 [10]3 years ago
8 0
If if a snail moves one six foot 12 hours the speed of the snail in you'll be alright you got to subtract 1/6 + 1/2 + 2/12=6
antoniya [11.8K]3 years ago
7 0
I hope this helps you




if snail moved 1/6 foot in 1/2 hour

? foot in 1 hour



?.1/2=1.1/6


?=2.1/6


?=1/3 foot per hour
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$13,957 is invested, part at 7% and the rest at 6%. If the interest earned from the amount invested at 7% exceeds the interest e
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Answer:

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The Amount invested at 6% interest = $1,102  

Step-by-step explanation:

Given as :

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And The money invested at 6% = p_2 = $13957 - $A

Let The interest earn at 7% = I_1

And The interest earn at 6% = I_2

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Let The time period = 1 year

Now,<u> From Simple Interest method</u>

Simple Interest = \dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}

Or,  I_1 = \dfrac{\textrm p_1\times \textrm 7\times \textrm 1}{100}

Or,  I_1 = \dfrac{\textrm A\times \textrm 7\times \textrm 1}{100}

And

I_2 = \dfrac{\textrm p_2\times \textrm 6\times \textrm 1}{100}

Or,  I_2 = \dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100}

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So, \dfrac{\textrm A\times \textrm 7\times \textrm 1}{100} -  \dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100} = $833.73

Or, 7 A - 6 (13,957 - A) = $833.73 × 100

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Or, 13 A = $83373 + $83742

Or, 13 A = $167,115

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So, The Amount invested at 7% interest = A = $12,855

And The Amount invested at 6% interest = ($13,957 - A) = $13,957 - $12,855

I.e The Amount invested at 6% interest = $1,102

Hence,The Amount invested at 7% interest is $12,855

And The Amount invested at 6% interest = $1,102   . Answer

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