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polet [3.4K]
2 years ago
5

Pleaseeee help me out

Mathematics
2 answers:
natulia [17]2 years ago
7 0

Answer:

U-60

S-90

Q-80

ur welcome

Diano4ka-milaya [45]2 years ago
4 0

Answer:

78

Step-by-step explanation:

QT is a 180 straight line so 180-55-47

Hope its right!

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I need the answer now please
xxMikexx [17]

Answer:

180/147

Step-by-step explanation:

We need to find the additive inverse of the given numbers.

  • For finding it we may simply out -1 as multiplication in front of the terms .

<u>SOLUTION</u><u> </u><u>1</u><u> </u><u>:</u><u>-</u>

→ 3/-7 - 11/21

→ -3/7 -11/21

→ 3×-3 - 11 /21

→ -9-11/21

→ -20/21

<u>SOLUTION</u><u> </u><u>2</u><u> </u><u>:</u><u>-</u><u> </u>

→ 9/5 ÷ 7/5

→ 9/5 × 5/7

→ 9/7

→ Product of nos . = -20/21 × -9/7

→ Ans = 180/147

7 0
3 years ago
Whats the answer giving brainliest :))))) lol
n200080 [17]

Answer:

B

Step-by-step explanation:

1+1=2

But 2x has to stay the same

5 0
2 years ago
sam's music teacher told him to practice his trombone for X amount of hours. he spent X amount of hours practicing did he practi
Crank
Yes if he practices X amount of hours and is told to practice X amount of hours than he practiced long enough
4 0
3 years ago
The weight, w, of a spring in pounds is given by 0.9 times the square root of the energy, E, stored by the spring in joules. If
frutty [35]
For this case we have the following equation:
 w = 0.9* \sqrt{E}
 Where,
 w: The weight of a spring in pounds
 E: the energy stored by the spring in joules.
 Substituting values we have:
 w = 0.9* \sqrt{12}
 Making the corresponding calculation:
 w=3.12
 Answer:
 
the approximate weight of the spring in pounds is:
 
w=3.12
4 0
3 years ago
Read 2 more answers
Find the distance from the point (1, 4) to the line y = 1/3x – 3.
Otrada [13]

Answer: Distance between line and point =

4√5 -3/2√10

Step-by-step explanation:

Distance between the line is

= √ ((9-0)²+(0+1)²)

= √ (89+1)

= √90

= 3√10

Half of the line = 3/2√10

Distance of one side of the line and the point.

= √((9-1)²+(0-4)²)

= √((8)²+(-4)²)

=√64+16

= √80

= 4√5

Distance between line and point =

4√5 -3/2√10

8 0
3 years ago
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