Can someone please help me with question 1, I will mark you as a brainest and I'll thank you
1 answer:
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<u>Answer: </u>
The point slope form of the line that passes through (-8,2) and is parallel to a line with a slope of -8 is 8x + y + 62 = 0
<u>Solution: </u>
The point slope form of the line that passes through the points and parallel to the line with slope “m” is given as
--- eqn 1
Where “m” is the slope of the line.
are the points that passes through the line.
From question, given that slope “m” = -8
Given that the line passes through the points (-8,2).Hence we get
By substituting the values in eqn 1, we get the point slope form of the line which is parallel to the line having slope -8 can be found out.
y-2=-8(x-(-8))
On simplifying we get
y – 2 = -8(x +8)
y – 2 = -8x -64
y – 2 +8x +64 = 0
8x + y +62 = 0
Hence the point slope form of given line is 8x + y +62 = 0
Answer:
area of trapezoid/trapezium =
h=height
a and b are the parallel sides (top 2.5 and bottom 6 in this pic)
so