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Artemon [7]
2 years ago
14

A point f(–3, 1) is translated along the vector ⟨5, –1⟩.what are the coordinates of the image f′ ?

Mathematics
1 answer:
jekas [21]2 years ago
7 0
(2.0)

Hope this helped :)
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40 fifth graders went to a school trip 25%of the students went to see the space exhibit how many students is that
Zielflug [23.3K]
The answer would A. 20 students
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What is 50% of one third
zloy xaker [14]

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-⅙ Im pretty sure this right

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Jenny wants to rent a truck for one day. She contacted two companies. Laguana's Truck Rentals charges $20 plus $2 per mile. Salv
Anna71 [15]

Answer:

20 miles.

Step-by-step explanation:

Let m be number of miles.

Laguana's Truck Rentals charges $20 plus $2 per mile.

Total cost of Laguana's Truck = 20+2m         .... (1)

Salvatori's truck rentals charges $3 per mile.  

Total cost of Salvatori's truck = 3m          ... (2)

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5 0
3 years ago
Find the 58"" term of the following arithmetic sequence,<br> 18, 23, 28, 33,
Anna11 [10]

Answer:

303

Step-by-step explanation:

So the equation to find a term is An=a1+(n-1)d

An represents the value of the number (n)

and n is the selective that you want

d is the difference between the first and second term which is 23-18=5, and you can see that adding 5 to the previous term gives the following term.

a1 is the first term in the sequence

so knowing all that now you can go back and inset all variables into the equation

An=18+(58-1)5

An=303

Hope that helps :)

Please give brainliest

6 0
3 years ago
PLZZZZ HELLPPP MEEE GET ANSWER
nadya68 [22]

Answer:

<em>See above photograph</em>

Step-by-step explanation:

This is how your graph will look like with an x-intercept of [−5, 0] (will not see, according to the scale, but on my device, you can), and a y-intercept of [0, 50]. The way to figure out all the coordinates upon this scale is to simply create a y-x value chart. Plug in each input value [x-value] to get your output value [y-value]:

<u>x|y</u>

0|50

1|60

2|70

3|80

4|90

5|100

6|110

7|120

8|130

9|140

10|150

11|160

Then, you simply just draw your line based of this chart.

I am joyous to assist you anytime.

4 0
3 years ago
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