Solve for x:
x^9 = n x
Subtract n x from both sides:
x^9 - n x = 0
Factor x and constant terms from the left hand side:
-x (n - x^8) = 0
Multiply both sides by -1:
x (n - x^8) = 0
Split into two equations:
x = 0 or n - x^8 = 0
Subtract n from both sides:
x = 0 or -x^8 = -n
Multiply both sides by -1:
x = 0 or x^8 = n
Taking 8^th roots gives n^(1/8) times the 8^th roots of unity:
Answer: x = 0 or x = -n^(1/8) or x = -i n^(1/8) or x = i n^(1/8) or x = n^(1/8) or x = -(-1)^(1/4) n^(1/8) or x = (-1)^(1/4) n^(1/8) or x = -(-1)^(3/4) n^(1/8) or x = (-1)^(3/4) n^(1/8)
To solve this problem you must apply the proccedure shown below:
1- You must rewrite each value shown in the picture attached, in decimal form, as following:
6π-6=12.84
π^3=31
√99=9.94
2- Now, you can order the values from least to greatest:
√99
6π-6
π^3
The answer is:
√99
6π-6
π^3
Answer: the answer is 8
Step-by-step explanation: First, you multiply 10 x 4. After that, you divide the answer, 40, by 5. After that you add 11 and then subtract 11, making 11 and 11 cancel out. So the answer is 8.
