Answer:
Explanation:
1. Temperature of the bottle when only helium gas was present :T
P= 1.83 atm
V = 2.50 L
n = 0.458 moles
Using an Ideal gas equation:
PV=nRT
T= PV/nR= 1.83*2.50/0.458* 0.0821 =121.81K
2. Temperature of the bottle when argon gas is added into the container:T'
P' =2.05 atm
V = 2.50 L
n' = 0.458 mol + 0.713 mol = 1.171 mol
PV=nRT
T= PV/nR = 1.83*2.50/1.171*0.0802 = 53.37
The change in temperature will be
Final temperature = Initial temperature:T' - T
53.37 k - 121.81 K = -68.44 K
The change in temperature of the gas mixture is -68.44 K.
