Solve first for the number of moles of sodium given that the mass is 2500 g by dividing the given mass by the molar mass of sodium.
moles sodium = 2500 g / 23 g/mol
moles sodium = 108.7 moles
Since in every mole of NaCl, there is only one mole of sodium then, we conclude that there are also 108.7 moles of NaCl. Multiplying the number of moles to the molar mass of sodium chloride (58.44), the answer would be 6,352.17 grams.
Explanation:
Immunoglobulin M is the first antibody produced on initial exposure to an antigen. It is also known as IgM.
It occurs as a primary response to the antigens against a particular baterium or virus. It is pentavalent in nature and has ten binding sites for antigens.
Therefore, it is concluded that when the body identifies a bacterium or a virus, it releases the antibody IgM.
Answer:
When writing equation the mass on left side of equation must be equal to the mass on right side. True
Explanation:
The chemical reactions always follow the law of conservation of mass.
Law of conservation of mass:
According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.
Explanation:
This law was given by french chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.
For example:
In photosynthesis reaction:
6CO₂ + 6H₂O + energy → C₆H₁₂O₆ + 6O₂
there are six carbon atoms, eighteen oxygen atoms and twelve hydrogen atoms on the both side of equation so this reaction followed the law of conservation of mass because total mass is equal on both side of equation.
Molarity is defined as the ratio of number of moles to the volume of solution in litres.
The mathematical expression is given as:
Here, molarity is equal to 1.43 M and volume is equal to 785 mL.
Convert mL into L
As, 1 mL = 0.001 L
Thus, volume = = 0.785 L
Rearrange the formula of molarity in terms of number of moles:
n =
= 1.12255 mole
Now, Number of moles =
Molar mass of potassium hydroxide = 56.10 g/mol
1.12255 mole =
mass in g =
= 62.97 g
Hence, mass of = 62.97 g
The reaction formula CH4 + 2O2 → CO2 + 2H2O shows the oxidation of 1 mole of CH4 (Methane) will yield 1 mole of CO2 (Carbon Dioxide). Since 1 mole of CH4 will weigh 12g (for the Carbon) + 4g (1g for each Hydrogen) = 16g, then 32g of CH4 will correspond to 32g / 16g/mole = 2 moles. Therefore the oxidation of 2 moles of CH4 will yield 2 moles of CO2.