One hypothesis that explains the result is : A) Two genes are involved with 12:3:1 epistasis, such that A_B_ and A_bb are black, aaB_ is brown,and aabb is green.
Explanation:
- This is a case of Dominant Epistasis.
- When two genes are involved and presence of dominant allele of one gene masks the effect of either allele of the second gene then the epistasis is termed as dominant epistasis.
- In the given case black :brown: green ratio is approximately equal to 12:3:1.
- Here presence of a dominant A allele that is responsible for the black colour masks the effect of either allele of B. Therefore A_B_ and A_bb produces black beetles
- Again , absence of dominant A allows B to express itself and Brown beetles are produced thus aaB_ is brown.
- When both the genes are present as recessive alleles, neither brown nor black colour is expressed and the beetles are green.Thus, aabb are green.
<span>Meiosis is the process of cell division that reduces the chromosome number by half. During the process two phases (two nuclear divisions) occur: Meiosis I and Meiosis II. Meiosis I is the phase of reduction and Meiosis II is the division. So, if a cell under a microscope shows two daughter cells and they aye haploid than this is the stage Meiosis II, in which the cell is divided into two daughter cells.</span><span />
Answer:
Because of the difference in surface area to volume ratio
Explanation:
Surface are to volume ratio is the area of an object that is exposed to the external environment (surface area), compared to the amount within an object (volume).
Therefore an elephant has a lower surface area to volume ratio than a mouse.
The smaller an object is the greater its surface area to volume ratio.
Small animals have much more surface area per mass than large animals. With so much surface area, they lose heat very quickly. So, a mouse, with a lot of surface area per mass, must spend a lot more energy to stay warm than a large animal.
