Given:
![f(x)=\sqrt[]{5x^2-2}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B%5D%7B5x%5E2-2%7D)
f(X) will be differentiated by chain rule.
![\begin{gathered} f^{\prime}(x)=\frac{1}{2\sqrt[]{5x^2-2}}\lbrack5(2x)\rbrack \\ f^{\prime}(x)=\frac{5x}{\sqrt[]{5x^2-2}} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20f%5E%7B%5Cprime%7D%28x%29%3D%5Cfrac%7B1%7D%7B2%5Csqrt%5B%5D%7B5x%5E2-2%7D%7D%5Clbrack5%282x%29%5Crbrack%20%5C%5C%20f%5E%7B%5Cprime%7D%28x%29%3D%5Cfrac%7B5x%7D%7B%5Csqrt%5B%5D%7B5x%5E2-2%7D%7D%20%5Cend%7Bgathered%7D)
Answer:
Step-by-step explanation:
Answer
x=12
Step-by-step explanation:
Answer:
For purple;
P(p) = 337/848 = 0.40
For white;
P(w) = 511/848 = 0.60
Step-by-step explanation:
Given;
Number of plants with purple flowers P = 337
Number of plants with white flowers W = 511
Total T = 337 + 511 = 848
For purple;
the empirical Probability that a plant had purple flowers P(p) is
P(p) = Number of plants with purple flowers/total number of plants
P(p) = P/T
Substituting the values, we have;
P(p) = 337/848 = 0.40
For white;
the empirical Probability that a plant had white flowers P(w) is
P(w) = Number of plants with white flowers/total number of plants
P(w) = W/T
Substituting the values, we have;
P(w) = 511/848 = 0.60
Answer;
64
Step-by-step explanation:
eee 4*4*4=64
sorry if im wrong, since it's a square than all the sides are the same, if it is a 3d CUBE then the area is 64 but if you're talking about a 2d square then its 16
