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rewona [7]
3 years ago
5

Grant is paining a rectangular board that has a width of 1/3 foot. He has enough paint to cover 3 square feet. If he is able to

cover the whole board by using all of his paint, what is th length of the board in feet?
Mathematics
1 answer:
k0ka [10]3 years ago
4 0
The Answer Should be 1
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∆ABC has A(-3, 6), B(2, 1), and C(9, 5) as its vertices. The length of side AB is units. The length of side BC is units. The len
leonid [27]

Answer:

AB = 7.07 units

BC = 8.06 units

AC = 12.04 units

Step-by-step explanation:

To find the length for each side of the triangle, apply the distance formula between each pair of vertices.

<u>AB</u>

d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(2--3)^2 + (1-6)^2} \\d = \sqrt{(5)^2 + (-5)^2} \\d = \sqrt{25 + 25} \\d = \sqrt{50} \\d=7.07

<u />

<u>BC</u>

d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(9-2)^2 + (5-1)^2} \\d = \sqrt{(7)^2 + (4)^2} \\d = \sqrt{49 + 16} \\d = \sqrt{65} \\d=8.06

<u />

<u>AC</u>

d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2} \\d = \sqrt{(9--3)^2 + (5-6)^2} \\d = \sqrt{(12)^2 + (-1)^2} \\d = \sqrt{144 + 1} \\d = \sqrt{145} \\d=12.04

4 0
3 years ago
h(x) = x^2 + 2x - 24 / x^2 + 10x + 25 Describe the behavior of the function h around its vertical asymptote at x = -5 ​
Vitek1552 [10]
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2 years ago
Find the measure of the exterior Angle1 (I’m a bit confused on how exterior angles work)
sergejj [24]

Answer:

70

Step-by-step explanation:

I would do 40 + 30 = 70

180-70 = 110

110 is the last angle bc all angles add to 180 in a triangle

Then 180 - 110 = 70 for angle 1 because their supplementary

I don't know if you could just add the 2 inside angles but I would do it this way to be safe until I know for sure.

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Which of the following should be your top priority? (1 point
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Answer:

paying down high-interest credit cards.

NOT SURE BUT BELIEVE ITS THAT.

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2 years ago
The temperature was 2° below zero the temperature drops by 5° what is the temperature now
Law Incorporation [45]

-2° was the initial temperature as it dropped to -5°
-2-5=-7
Hope this helped

4 0
3 years ago
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