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3 years ago

5

Grant is paining a rectangular board that has a width of 1/3 foot. He has enough paint to cover 3 square feet. If he is able to

cover the whole board by using all of his paint, what is th length of the board in feet?

1 answer:

k0ka [10]3 years ago

4 0

The Answer Should be 1

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Diano4ka-milaya [45]

It will be 3 hours until they are the same hight

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3 years ago

Mrs. Bhatia's closet consists of two sections, each shaped like a rectangular prism. She plans to buy mothballs to keep the moth

AveGali [126]

Answer:

6.5 boxes

Step-by-step explanation:

Given

See attachment for closet

Required

Determine the number of boxes needed to fill the closet

First, we calculate the volume of the two section.

According to the attachment

The first section has the following dimension:

$Width = 5ft$

$Length = 4ft$

$Height = 8ft$

The second has the following dimension:

$Width = 3ft$ ---- see the last label at the top

$Length = 2ft$ --- This is calculated by subtracting the length of the first section (4ft) from the total length of the closet (6ft) i.e. 6ft - 4ft

$Height = 8ft$

So: The volume of the closet is:

$Volume = W_1 * L_1 * H_1 + W_2 * L_2 * H_2$

$Volume = 5ft * 4ft * 8ft + 3ft * 2ft * 8ft$

$Volume = 160ft^3 + 48ft^3$

$Volume = 208ft^3$

The number of box needed is then calculated by dividing the volume of the closet (208ft^3) by the volume of each box (32ft^3)

$Boxes = \frac{208ft^3}{32ft^3}$

$Boxes= \frac{208}{32}$

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3 years ago

Gillian eats 12 skittles. If there was originally 25 skittles in the bag, what percent of the skittles did Gillian eat? (NOT A S

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3 years ago

What is the probability of getting 6 as a product explanation and calculation

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For an individual die roll, the probability of rolling 6 is \dfrac{1}{6}

6

1

.

Effectively, this problem is asking for P(\text{1st roll is 6}\cap\text{2nd roll is 6})P(1st roll is 6∩2nd roll is 6).

Using the rule of product, this is:

\dfrac{1}{6}\times\dfrac{1}{6}=\dfrac{1}{36}

6

1

×

6

1

=

36

1

.

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2 years ago

You want to calculate the displacement of an object thrown over a bridge. Using -10 m/s^2 for acceleration due to gravity, what

MrRissso [65]

<u>Answer</u>

<em>The total displacement of the object is 320 m</em>

<u>Solution-</u>

From the formulas of mechanics,

$s=ut+\frac{1}{2}at^{2}$

Where,

s = displacement

u = initial velocity = 0 ( ∵ As the body was in rest in the beginning )

t = time taken = 8 s

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Putting all the values,

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4 years ago