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Savatey [412]
3 years ago
13

With her new trainer, Judy now bikes at an average speed of 24.1 MPH. That is 20.5% faster than she averaged with her old traine

r. How fast did she bike, on average, before training with the her new trainer?
Mathematics
2 answers:
marishachu [46]3 years ago
5 0

Answer: an average of 13.5 mph is very respectable

Step-by-step explanation:

noname [10]3 years ago
4 0

Answer:

an average of 13.5

Step-by-step explanation:

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Find the pattern, then write the next two letters.<br> J, F, M, A, M,_, _
RoseWind [281]

Answer:

its answer J,F,M,A,M,J,J

Step-by-step explanation:

<h3>its a name of months next 5 words is A,S,O,N,and D</h3>
5 0
3 years ago
Read 2 more answers
There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In
Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the <em>sampling distribution of the sampling proportions</em>.

The mean and standard deviation of this sampling distribution is:

\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

P(0.45

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

P(p>0.8)=P(z>z^*)

The z value is calculated as before:

z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0
2 years ago
What is always the smallest positive factor of any positive integar?​
Ulleksa [173]

Answer:

1

Step-by-step explanation:

The smallest positive factor is 1

But not 0 because 0 is not positive nor negative

4 0
3 years ago
Please I need x and y
Kryger [21]
It could be anything they are both variables.
3 0
3 years ago
2 (2f+2)= help me fast
8_murik_8 [283]

Distribute

2 × 2f + 2 × 2

Simplify 2 × 2f to 4f

4f + 2 × 2

Simplify 2 × 2 to 4

<u>4f + 4</u>

4 0
3 years ago
Read 2 more answers
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