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Anna71 [15]
3 years ago
11

A line contains the points (-1, 6), (6, k) and (20, 3). What is the value of k?

Mathematics
1 answer:
AURORKA [14]3 years ago
7 0
Consider, pls, this option:
1. if a required line has a form y=ax+b, then points A(-1;6); B(6;k) and C(20;3) belong to it.
2. According to the item 1 it is possible to make up the system of equations for A and C:
\left \{ {{-a+b=6} \atop {20a+b=3}} \right \  \left \{ {{a=- \frac{1}{7} } \atop {b= \frac{41}{7} }} \right.
Knowing, that a=-1/7 and b=41/7, it is possible to write the equation of required line:
y=- \frac{1}{7}x+ \frac{41}{7}
3. Using coordinates of point B:
k=- \frac{6}{7}+ \frac{41}{7} =5 \ where \ k=y

Answer: 5.
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7(x-2) - 3x + 5 = -2 (5x-4) + 4<br> Please help asap! - xxx
Oxana [17]

Answer:

x=

2

3

​

=1.500

Step-by-step explanation:

(((7•(x-2))-3x)+5)-((0-2•(5x-4))+4)  = 0

STEP

2

:

Equation at the end of step 2

 ((7 • (x - 2) -  3x) +  5) -  (12 - 10x)  = 0

STEP

3

:

STEP

4

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Pulling out like terms

4.1     Pull out like factors :

  14x - 21  =   7 • (2x - 3)

Equation at the end of step

4

:

 7 • (2x - 3)  = 0

STEP

5

:

Equations which are never true

5.1      Solve :    7   =  0

This equation has no solution.

A  non-zero constant never equals zero.

Solving a Single Variable Equation:

5.2      Solve  :    2x-3 = 0

Add  3  to both sides of the equation :

                     2x = 3

Divide both sides of the equation by 2:

                    x = 3/2 = 1.500

One solution was found :

x = 3/2 = 1.500

5 0
3 years ago
Read 2 more answers
Rewrite 5 2/3 as an improper fraction.
kupik [55]
5 2/3 would be 3 times 5 +2 think of it as starting the letter C from the bottom to the top multiply the bottom and middle add the top

If you do that you should get 17/3
6 0
3 years ago
What is the slope of the line through the points (8, -2) and (8, -8)?
gulaghasi [49]

Answer:

Step-by-step explanation:

(-8+2)/(8-8)= -6/0= undefined

8 0
3 years ago
PLEASE HELP ASAP
maria [59]

Answer:

First option:  3x^2-5x=-8

Second option: 2x^2=6x-5

Fourth option: -x^2-10x=34

Step-by-step explanation:

Rewrite each equation in the form ax^2+bx+c=0 and then use the Discriminant formula for each equation. This is:

D=b^2-4ac

1) For 3x^2-5x=-8:

 3x^2-5x+8=0

Then:

D=(-5)^2-4(3)(8)=-71

Since D this equation has no real solutions, but has two complex solutions.

2) For 2x^2=6x-5:

 2x^2-6x+5=0

Then:

D=(-6)^2-4(2)(5)=-4

Since D this equation has no real solutions, but has two complex solutions.

3) For 12x=9x^2+4:

 9x^2-12x+4=0

Then:

D=(-12)^2-4(9)(4)=0

Since D=0 this equation has one real solution.

4) For -x^2-10x=34:

 -x^2-10x-34=0

Then:

D=(-10)^2-4(-1)(-34)=-36

Since D, this equation has no real solutions, but has two complex solutions.

3 0
3 years ago
The set of all Real numbers between 4 and 7 including 4
erik [133]
4,5,6,7 is your answer
8 0
2 years ago
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