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aev [14]
3 years ago
11

The hypotenuse of a right triangle has a length of 14 units and a side that is 9 units long. which equation can be used to find

the length of the remaining side?
Mathematics
2 answers:
lions [1.4K]3 years ago
4 0

Answer:

The equation used is

(\text{Remaining side})^2=14^2-9^2  

Step-by-step explanation:

Given that the hypotenuse of a right triangle has a length of 14 units and a side that is 9 units long.

we have to find the equation which is used to find the length of the remaining side.

In right angled triangle Pythagoras theorem can be used to find the length of one side if two sides are given as

Hypotenuse^2=(one \thinspace side)^2+(other\thinspace side)^2

14^2=9^2+(\text{Remaining side})^2

(\text{Remaining side})^2=14^2-9^2

which is required equation

Virty [35]3 years ago
3 0
Using the Pythagorean therom.

9^{2} + b^{2} = 14^{2}
81 + b^{2} = 196
b^{2} = 115
b = \sqrt{115}

Hope this helps!
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The function h(x)=x² +5 maps the domain given by the set {-2, -1, 0, 1, 2}. Which of the following sets
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For the given function h(x) = x² +5 ,the domain of the function h(x) maps by the set { -2, -1, 0, 1, 2 } then the range of the function h(x) is given by the set { 5, 6, 9 } .

As given in the question,

Given function is equal to :

h(x) = x² +5

Domain of the function h(x) = x² +5 maps by the set { -2, -1, 0, 1, 2 }

Range of the function h(x) = x² +5 is represented by the set as follow :

Substitute the value x = -2, -1, 0, 1, 2 in the function h(x) = x² +5 we get,

h(-2) = (-2)² + 5

       = 9

h(-1) = (-1)² + 5

       = 6

h(0) = (0)² + 5

       = 5

h(1) = (1)² + 5

       = 6

h(2) = (2)² + 5

       = 9

Range of the function is represented by the set : { 5, 6, 9 }

Therefore, for the given function h(x) = x² +5 ,the domain of the function h(x) maps by the set { -2, -1, 0, 1, 2 } then the range of the function h(x) is given by the set { 5, 6, 9 }.

Learn more about function here

brainly.com/question/12426369

#SPJ1

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