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4 years ago

Could someone please help me with this problem

Mathematics

1 answer:

kari74 [83]4 years ago

4 0

The answer is choice three

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Determine whether each graph represents a function

grandymaker [24]

It is the graph in the middle because x can only have one y.
Hope that this helps :)

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3 years ago

If eight is added to four times a number the results is 96?

malfutka [58]

Answer:

Step-by-step explanation:

let the x be the number

8+4x=96

4x=96-8

4x=88

x=88/4

x=22

check: 8+4(22)=8+88=96

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3 years ago

Which function has (3,2) on its graph

Dominik [7]

Answer:

C.) y = -2/3x + 4

4 0

4 years ago

Read 2 more answers

Use the polar representation to write the following in the form a + bi (a) (-1+ i)^7 (b) (1+v3i)^10

ira [324]

Answer with Step-by-step explanation:

For any complex number x+iy the polar form is represented as

$z=re^{i\theta }$

where

$r^{2}=x^2+y^2\\\\tan(\theta )=\frac{y}{x}$

Part a) x+iy = -1+i

Thus $r=\sqrt{-1^2+1^2}=\sqrt{2}\\\\ \theta _{1}=tan^{-1}(\frac{-1}{1})=\frac{-\pi }{4}$

Thus using De-Morvier's theorem

$(-1+i)^7=(\sqrt{2}e^{i\frac{-\pi }{4}})^7\\\\\therefore (-1+i)^7=2^{7/2}\cdot e^{\frac{i-\pi }{28}}$

Part 2) x+iy = 1+3i

Thus $r=\sqrt{1^2+3^2}=\sqrt{10}\\\\ \theta _{1}=tan^{-1}(\frac{3}{1})=1.25$

Thus using De-Morvier's theorem

$(1+3i)^{10}=(\sqrt{10}e^{1.25i})^{10}\\\\\therefore (1+3i)^{10}=10^{5}\cdot e^{12.5i}$

3 0

3 years ago

The two shorter sides of a triangle are the same length. the length of the longer side is 5 m longer than each of the shorter si

ziro4ka [17]

P=a+b+c. Sub in what we know: 29=a+a+(a+5). Combine like terms: 29=3a+5. Subtract 5 from both sides: 24=3a. Divide by 3: 8=a. Short sides: A=8m, b=8m, long side: c=13m. :)

4 0

3 years ago