4 years ago

Could someone please help me with this problem

1 answer:

4 0

The answer is choice three

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Alchen [17]

what is the best and easiest method to use to find sides A and B?

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3 years ago

goblinko [34]

The answer is D
Let me know if it’s right!

8 0

3 years ago

kherson [118]

Answer:

The answer is

$f(x) = {\displaystyle 8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }$

Step-by-step explanation:

Remember that Taylor says that

$f(x) = {\displaystyle \sum\limits_{k=0}^{\infty} \frac{f^{(k)}(a) }{k!}(x-a)^k }$

For this case

$f^{(0)} (-2) = 8(-2)-3(-2)^3 = 8\\f^{(1)} (-2) = 8-3(3)(-2)^2 = -28\\f^{(2)} (-2) = -3(3)2(-2) = -36\\f^{(2)} (-2) = -3(3)2 = -18$

$f(x) = {\displaystyle 8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }$

5 0

3 years ago

finlep [7]

Answer:

Step-by-step explanation:

Y=mx=b

m= slope

b= y- intercept

x&y are variables

7 0

3 years ago

Crank

Answer:

Any numbers above -5 make this inequality true. Values that will make the inequality true: -4, -3, -2, -1, 0, 1...

6 0

3 years ago