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Stolb23 [73]
3 years ago
12

________ is a password-cracking method wherein the attacker compares passwords to lists of common words.

Computers and Technology
1 answer:
Dmitriy789 [7]3 years ago
7 0
Hi!

When someone repeatedly compares passwords to lists of common words, this is known as the dictionary attack.

We call it this because they are <em>literally </em>using a dictionary to attack you!

Hopefully, this helps! =)
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The answer to this question is given below in this explanation section.

Explanation:

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Importance:

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Managing cyber security:

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Answer:

See explaination for Program source code.

Explanation:

The program source code below.

#include <iostream>

#include <fstream>

#include <vector>

using namespace std;

class Show

{

private:

string title;

int viewers;

public:

Show()

{

this->title = "";

this->viewers = 0;

}

Show(string title, int viewers)

{

this->title = title;

this->viewers = viewers;

}

string getTitle(){ return this->title; }

int getViewers(){ return this->viewers; }

};

int main()

{

vector<Show> shows;

vector<string> titles;

vector<int> viewers;

ifstream inFile1("file1.txt");

ifstream inFile2("file2.txt");

string line1, line2;

if(!inFile1.is_open() || !inFile2.is_open())

{

cout << "Either of the files could not be found!\n";

exit(0);

}

getline(inFile1, line1);

if(line1.compare("Show") == 0)

{

while(getline(inFile1, line1))

{

titles.push_back(line1);

}

inFile1.close();

}

getline(inFile2, line2);

if(line2.compare("Viewer") == 0)

{

while(getline(inFile2, line2))

{

viewers.push_back(stod(line2));

}

inFile2.close();

}

for(int i = 0; i < titles.size(); i++)

{

shows.push_back(Show(titles[i], viewers[i]));

}

// display all the show details

cout << "\nALL SHOWS:\n----------\n";

for(Show show : shows)

{

cout << "Title: " << show.getTitle() << ", Number of viewers: " << show.getViewers() << endl;

}

cout << endl;

return 0;

}

See attachment for output

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