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Pavlova-9 [17]
2 years ago
12

Javier downloads an illustration from an online Image library and modifies it for his purposes. The illustration he downloads is

licensed under the
Creative Commons Attribution-ShareAlike (CC BY-SA) license. What three things does he need to do to comply with the terms of the license?
o charge a fee for use of his Image
Opermit others to make derivatives of his Image
0 0 0 0 0
acknowledge the source of his Image
restrict the use of his image to noncommercial purposes
license his image under identical terms as the illustration he uses
Computers and Technology
1 answer:
Kaylis [27]2 years ago
8 0

The three things he needs to do to comply with the terms of the license are:

  1. Permit others to make derivatives of his Image.
  2. Acknowledge the source of his Image.
  3. License his image under identical terms as the illustration he uses.

<h3>What is the Creative Commons Attribution-ShareAlike (CC BY-SA) license?</h3>

This type of license is one that allows the person who requires an image with said license to use it, even modify it so that the resulting image has the deserved attribution to the person who made the original image and that the resulting image has the same license as the original.

For these reasons, it is forbidden for an image resulting from another with the aforementioned license to be placed in an image bank under payment.

If you want to learn more about Creative Commons License, you can visit the following link: brainly.com/question/17496633

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A 4-way set associative cache has 64 blocks of 16 words. How many bits are there in the ""tag"" field of the 15-bit address for
Tanya [424]

Answer:

3 bits

Explanation:

Given a 4- way set associative cache that has 64 blocks of 16 words.

Therefore, the number of sets cache has:

\frac{64}{4} = 16

Now,

Cache data size is 16kB

The number of cache blocks can be calculated as:

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Now,

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Now,

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A new folder can be created by
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Define a function called strip_punctuation which takes one parameter, a string which represents a word, and removes characters c
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Answer:

punctuation_chars = ["'", '"', ",", ".", "!", ":", ";", '#', '@']

def strip_punctuation(strWord):

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Explanation:

The function is defined with a single argument.

A for loop is ran to check each character of the the word.

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