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kirill [66]
4 years ago
5

message me if u can help with algebra 2

Mathematics
1 answer:
Over [174]4 years ago
4 0
I wish I could help but I’m taking it right now too. I’m struggling lol
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Can someone give me the answers for number 3 ? With explanation please?
Olegator [25]
6^{51}6^{48} = 6^{51 + 48}= 6^{99}

(6^5)^7 = 6^ {5 \times 7} = 6^ {35}

6(6^{25}6^{14}) = 6(6^{25+ 14}) = 6(6^{39}) = 6^{39 + 1}= 6^{40}

\dfrac{6^{95}}{6^{19}} = 6^{95 - 19} = 6^{76}


4 0
4 years ago
Solve.<br> -52-3<br> 2<br> 21<br> -21<br> Dons -
muminat

Answer & Step-by-step explanation:

-52-3+2+21-21 =

-55+2+21-21 =

-53+21-21 =

-32-21 =

-53 =

3 0
3 years ago
Which equation is equivalent to f(x)=16x^4-81=0
Talja [164]
I'm pretty sure you are looking for factored forms as an equivalent equation, so here is how you do it. 
This equation would be solved by difference of squares. 16, x^4, and 81 are all perfect squares ( which means that it is a number multiplied by itself, 16 is 4 x4 for example). So the first thing you want to do is recall the formula which is
(a^2 - b^2) = (a - b)*(a + b) 
(16x^4 - 81)= 0
Find the sq. root of 16 which is 4, and of x^4 which is x^2, and 81 which is 9. Now re write it in the (a - b)*(a + b) format. ----> (4x^2 - 9)*(4x^2 + 9) = 0
7 0
3 years ago
Read 2 more answers
.07 is 10 times as much as what number
wariber [46]

0.7 is 0.07 times ten, and 0.7 times 10 is 7 :)

7 0
3 years ago
5/6 of the students completed homework last night, but only 3/4 of those students did their work correctly. How many students di
Kisachek [45]

Answer:


Step-by-step explanation:

first your going to do the least common multiple which is 12 for both then your going to subtract because were trying to find out how many students did there work correctly. so, whatever you do to the denominator you do to the numerator so, its going to be 10/12 - 9/12= 1/12 is your answer.

8 0
3 years ago
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