Answer:
Simplify {4}^{2}42 to 1616.
-16+2\times -4\times -5-2\times {2}^{3}−16+2×−4×−5−2×23
Simplify 2\times -42×−4 to -8−8.
-16-8\times -5-2\times {2}^{3}−16−8×−5−2×23
Simplify 8\times -58×−5 to -40−40.
-16-(-40)-2\times {2}^{3}−16−(−40)−2×23
Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}xaxb=xa+b.
-16-(-40)-{2}^{4}−16−(−40)−24
Simplify {2}^{4}24 to 1616.
-16-(-40)-16−16−(−40)−16
Remove parentheses.
-16+40-16−16+40−16
Simplify -16+40−16+40 to 2424.
24-1624−16
Simplify.
8
Step-by-step explanation:
hope it helps :)
First simplify the one inequality, 6r + 30 greater than or equal to 12 just divide by 6 then subtract 30 from both sides of the inequality. You should get r is greater than or equal to -3. For this one you need to reverse the inequality symbol then divide both sides by -1 to get a positive r, and you get r is less than -12. It's not A because there's two solutions, and it's not D for the same reason. It's not C because r isn't greater than -12. In conclusion it's B because it correctly represents the solutions that make the inequality true. I hope this helps you on your high school application :)
I think it’s gonna be 1-log(y). You use the quotient rule of logarithms.
C(1)=6
c(2)=c(2-1)-16=c(1)-16=6-16=-10
c(3)=c(3-1)-16=c(2)-16=-10-16=-26
