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3 years ago

Solve and type in a different form by using the given theorems of logarithms log (10/y)=

Mathematics

1 answer:

Ulleksa [173]3 years ago

4 0

I think it’s gonna be 1-log(y). You use the quotient rule of logarithms.

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Is y=3x-5 linear or non-linear? (A linear (B non-linear

WINSTONCH [101]

A...............................

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3 years ago

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What is the plce and value of the 2's in the#24229582

maks197457 [2]

1. 20,000,000 = 20 million
2. 200,000 = 200 thousand
3. 20,000 = 20 thousand
4. 2 = 2 ones? (I'm not sure about this one)

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3 years ago

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The second term of a GP is 4, the fifth term is 81. Find the seventh term

navik [9.2K]

Answer:

The seventh term of a G.P is

$t_{7} = 33,097.211$

Step-by-step explanation:

step(i):-

Given the second term of a G.P is '4'

The general term of nth term is

$t_{n} = ar^{n-1}$

$t_{4} = ar^{4-1} =4$

$ar^{3} =4$ …(i)

Also Given the fifth term of a G.P is '81'

$t_{5} = ar^{5-1} =81$

$ar^{4} =81$ …(ii)

Step(ii):-

Dividing the equation (ii) divided by (i)

$\frac{ar^{4} }{ar^{3} } = \frac{81}{4}$

cancellation ' a' and 'r' terms , we get

$r = \frac{81}{4}=20.25$

substituting 'r' Value in equation (i), we get

$ar^{3} =4$

$a(\frac{81}{4}) ^{3} =4$

$a = \frac{4X4X4X4}{(81)^{3} }= \frac{256}{531,441}$

a = 0.00048

Step(iii):-

The seventh term of G.P

The general term of nth term is

$t_{n} = ar^{n-1}$

$t_{7} = (0.00048)(20.25)^{7-1}$

$t_{7} = (0.00048)(20.25)^{6}= 33,097.211$

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4 years ago

Explain why the following is a relation

dangina [55]

The following is a relation because each x doesn’t only have one y; the following is a relation because two Ys have the same X

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3 years ago

The vertices of triangle ABC are A(5,2), B(-1,-6) and C(1,5). If Triangle DEF is similar to Triangle ABC and AB/DE=5, what could

astraxan [27]

Answer:

D(-5,3) and E(-5,1)

Step-by-step explanation:

|AB|² = (-1-5)² + (-6-2)²

|AB|² = 36 + 64

|AB|² = 100

|AB| = 10

AB/DE = 5

|DE| = 10/5 = 2

D(-5,3) and E(-5,1)

|DE|² = (-5+5)² + (3-1)²

|DE|² = 4

|DE| = 2

Verified

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3 years ago

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