Question

C(1)=6 c(n)=c(n-1)-16 Find the 3rd term in the sequence

Answer 1

C(1)=6
c(2)=c(2-1)-16=c(1)-16=6-16=-10
c(3)=c(3-1)-16=c(2)-16=-10-16=-26

Answer 2

Answer:

The 3rd term is -26.

Step-by-step explanation:

To find a term in this sequence, we just need to replace the value for the n. If we want to calculate the third term, we just use n=3, replace it and solve. However, in this case, the relation have this particular term c(n-1), this menas that the expression is like cycle. The operations would be like this:

For $n=2$:

$c(n)=c(n-1)-16\\c(2)=c(2-1)-16\\c(2)=c(1)-16$

Here we can see the term we mention before, the term c(1) refers to the given value 6, so we replace it.

$c(2)=6-16=-10$

Now, we repeat the process with $n=3$, which is the third term:

$c(n)=c(n-1)-16\\c(3)=c(3-1)-16\\c(3)=c(2)-16\\c(3)=-10-16=-26$

Therefore, the 3rd term is -26.