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4 years ago

What is the equation of the following line? Be sure to scroll down first to see

Mathematics

2 answers:

olchik [2.2K]4 years ago

6 0

Answer:

$y=6x$

Step-by-step explanation:

we have the ordered pairs

(0,0) and (-1/2,-3)

In this problem we have a proportional relationship, because the line passes through the origin

A proportional variation can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

Find the value of the constant of proportionality k

For x=-1/2, y=-3

$k=\frac{y}{x}$ ----> $k=\frac{-3}{(-1/2)}=6$

therefore

The linear equation is equal to

$y=kx$

substitute the value of k

$y=6x$

jeka944 years ago

4 0

Answer: Y=-6x

Step-by-step explanation:

APEX

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Given sec A = 5/3 and that angle A is in Quadrant I, find the exact value of csc A in simplest radical form using a rational den

serg [7]

9514 1404 393

Answer:

5/4

Step-by-step explanation:

The relationship between the sec and csc functions is ...

csc(A) = sec(A)/√(sec²(A) -1)

For the given value of sec(A), this is ...

csc(A) = (5/3)/√((5/3)² -1) = (5/3)/√(16/9) = (5/3)/(4/3)

csc(A) = 5/4

Some calculators can tell you the answer directly.

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3 years ago

Jasmine needs $26.73 to buy a shirt. She has $21.76 in her pocket. How much more money does Jasmine need?

SVETLANKA909090 [29]

Answer:

$4.97

Step-by-step explanation:

26.73 - 21.76

= 4.97

6 0

3 years ago

Please help me asap and

inn [45]

Answer: p < 5

Step-by-step explanation:

You subtract 5 from each side and end up with p < 5

7 0

3 years ago

Read 2 more answers

The parametric curve described by the equations x=\cos(t),\;\;y=\sin(t)\cos(t) has two tangent lines at (0, 0). find the equatio

mr Goodwill [35]

Hello,

$x=cos(t)==\ \textgreater \ \dfrac{dx}{dt} =-sin(t)\\
y= \dfrac{sin(2t)}{2}==\ \textgreater \ \dfrac{dy}{dt} =cos(2t)\\

 \dfrac{dy}{dx} = \dfrac{ \frac{dy}{dt}}{ \frac{dx}{dt} } =- \frac{cos(2t)}{sin(t)} \\
For\ x=0, \ t=cos(0)= \frac{ \pi }{2} +k \pi \\

( \dfrac{dy}{dx} )_{x=0} =\pm\ 1\\

tangents \ are\ \{ y=-x,y=x \}\\

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3 0

4 years ago

1/2x+1/3y=2

timofeeve [1]

Answer:

x=2

y=3

Step-by-step explanation:

x/2+y/3=2 so

3x/6+2y/6=12/6

then multiply by 6

3x+2y=12

equation number 2

x/3+y/2=13/6

2x/6+3y/6=13/6

multiply by 6

2x+3y=13

so the system is now

3x+2y=12

2x+3y=13

from the first equation 2y=12-3x, y=6 - 3x/2

then put y in the second equation

2x+3*(6-3x/2)=13

2x+18-9x/2=13

2x-9x/2=13-18

4x/2-9x/2=-5

-5x/2=-5

*(-1/5) *(-1/5)

x/2=1

*2 *2

x=2

so y=6-3*2/2=6-3

y=3

4 0

3 years ago