There are 232 nickels in $11.60.
This is because each nickel is worth 5 cents. So by multiplying 232 by 5 you will get 1,160.
Answer: m = 0
Step-by-step explanation: To find the slope of the line, we can use the graphing method. To do this, we start by plotting our two points.
Let's label (6, 1) as point A and (-6, 1) as point B.
Now, graph our line through the 2 points.
Now remember that the slope, or m, is equal to
the rise over run from point A to point B.
To get from point A to point B, we rise o units and run -12 units.
So our slope or rise / run is 0/-12 which simplifies to 0.
This should make sense because we have a horizontal or flat line and
remember that the slope of any horizontal or flat line is 0.
Image attached.
The cross of YyRr will produce 16 distinct genotypes.
If the two alleles are far enough on the same chromosome, then the Y and R alleles will be distributed independently of one another, so that the genotypic ratio among each allele would be 1:2:1 (YY:Yy:yy, and similarly for the R allele). Then the dihybrid cross will yield a genotypic ratio of 1:2:1:2:4:2:1:2:1 (YYRR:YYRr:YYrr:YyRR:YyRr:Yyrr:yyRR:yyRr:yyrr).
Now, assuming perfect Mendelian inheritance (complete dominance), the phenotypes exhibited by YY and Yy will be considered equivalent, and similarly for RR and Rr, so the phenotypic ratio would be 9:3:3:1 (YR:Yr:yR:yr).
9514 1404 393
Answer:
- The graph has an open circle at 7.
- The arrow points left.
Step-by-step explanation:
Adding 10 and dividing by 4, we have ...
4x < 28
x < 7
The comparison does not include the "equal to" case, so the circle at x=7 is open. Values of x less than 7 are in the solution set. Those values are found to the left of 7 on the number line.
- The graph has an open circle at 7.
- The arrow points left.
Answer:
<h2>A. 4t² - 32t + 64</h2>
Step-by-step explanation:
Instead of x put (t - 3) in the equation of the function f(x) = 4x² - 8x + 4:
f(t - 3) = 4(t - 3)² - 8(t - 3) + 4
<em>use (a - b)² = a² - 2ab + b² and the distributive property a(b + c) = ab + ac</em>
f(t - 3) = 4(t² - (2)(t)(3) + 3²) + (-8)(t) + (-8)(-3) + 4
f(t - 3) = 4(t² - 6t + 9) - 8t + 24 + 4
f(t - 3) = (4)(t²) + (4)(-6t) + (4)(9) - 8t + 28
f(t - 3) = 4t² - 24t + 36 - 8t + 28
f(t - 3) = 4t² + (-24t - 8t) + (36 + 28)
f(t - 3) = 4t² - 32t + 64
