Answer:
True
Explanation:
Assuming it to be true false question the given statement is true.
The given statement is absolutely correct that the user test and acceptance procedure is the last point at which the user can determine the system’s acceptability prior to it going into service.
Answer:
Note: The full question is attached as picture below
a. Equity income that the investor should report in its income = Net income * Investor share = 400,000 * 30% = $120,000
b. Particulars Amount
Equity investment opening 500,000
Add: Equity income 120,000
Less: Dividend paid <u>60,000</u>
Equity investment at end of year <u>560,000</u>
c. The fair value of the Investee company will remain at adjusted cost. and the investment is not adjusted to fair value
The answer is the UAC or also known as the User Account
Control. This will usually pop out on the screen to notify the individual using
the computer of whether he or she would want to make changes before he or she
exits a certain program or when there are changes made.
Answer:
a. What is the firm’s taxable income?
387.500
b. What is the tax expense?
81.375
Explanation:
You first need to determine Talley's taxable income:
Income after operating costs: $455,000
Less: Interest Expense -$70,000
Plus: Taxable Dividends Received 2,500
.
Taxable Income: 387.500
Federal tax rate 21%
Tax expense 81.375
Complete Question
A waiting line problem has an average of 250 arrivals per eight hour day. Suppose there are several servers, and each has an average service time of 8 minutes. (Assume Poisson arrivals and exponential service times.)
What is the average service rate of a server per hour?
Answer:
7½ arrivals per hour
Explanation:
Given
Arrivals = 250 arrivals per 8 hour day
Service Time of Servers = 8 minutes
The service time of Servers is given as 8 minutes.
This means that; on average, a server will attend to 1 arrival in every 8 minutes.
Calculating this per hour;
Average service rate of a server per hour = Service Rate * 1 hour per hour
Average service rate of a server per hour = 1 arrival per 8 minutes * 1 hour per hour
(1 hour = 60 minutes);
So, we have.
Average service rate of a server per hour = 1/8minutes * 60minutes/hour
= ⅛ * 60 arrivals/hour
= 60/8 arrivals/hour
= 7½ arrivals per hour