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yawa3891 [41]
3 years ago
14

Which of the following is not an assessment of your fitness to drive

Computers and Technology
1 answer:
Ivan3 years ago
3 0

Answer:

C. Am I carrying money?

Explanation:

The options are:

A. Am I awake and alert?

B. Am I emotionally sound?

C. Am I carrying money?

D. Am I physically able?

The correct option is certainly C. Am I carrying money? It can also be a concern if you are worrying since we don't have money. However, here its mentioned, we are not carrying, and it's not like we don't have money, and hence, it is not going to affect our mindset. Hence, it is not an assessment of anybody's fitness to drive.

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To execute a prepared SQL statement, you can use the ________________ and execute() methods of the PDOStatement object to set pa
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Answer:

The correct answer to the following question will be "bindValue".

Explanation:

  • The PDO declaration bind-value feature allows to bind a value or a function to a argument or a parameter.
  • To run a compensated statement of SQL, you could also use the PDOStatement object's bindvalue and execute() methods to set values of the paramenter or any argument and implement the comment.

Therefore, it's a right answer.

8 0
3 years ago
A drive is small enough to be carried in one's pocket.
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Answer: Pen

Explanation:

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You created the following dictionary relationships = {'Jimmy':'brother', 'Carol':'sister'}. You then executed the following code
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Answer:

This is because the key in relationships['jimmy'] is wrong. The first letter "j" should be uppercase. The key in the given dictionary is "Jimmy" and therefore a lowercase "j" will result in a KeyError exception. The key is case sensitive and therefore a minor mistake in a single letter either in lowercase or uppercase will cause the error. The correct usage of key to address the value should be relationships["Jimmy"].

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3 years ago
Part 1 of 4 parts for this set of problems: Given an 4777 byte IP datagram (including IP header and IP data, no options) which i
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Answer:

Fragment 1: size (1332), offset value (0), flag (1)

Fragment 2: size (1332), offset value (164), flag (1)

Fragment 3: size (1332), offset value (328), flag (1)

Fragment 4: size (781), offset value (492), flag (1)

Explanation:

The maximum = 1333 B

the datagram contains a header of 20 bytes and a payload of 8 bits( that is 1 byte)

The data allowed = 1333 - 20 - 1 = 1312 B

The segment also has a header of 20 bytes

the data size = 4777 -20 = 4757 B

Therefore, the total datagram = 4757 / 1312 = 4

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2nd threat

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