<span>END POINT : Snaps to the closest endpoint or corner of a geometric object. MID POINT : Snaps to the midpoint of a geometric object. CENTER : Snaps to the center of an arc, circle, ellipse, or elliptical arc.</span>
Answer:
a) 255
b) 61602
c)
d)
Explanation:
You need to understand the decimal equivalent of hexadecimal numbers, <em>from 0 to 9 numbers are represented the same way, from 10 to 15 we use the alphabet, meaning 10 equals A in hexadecimal base, 11-B, 12-C, 13-D, 14-E, and 15-F.</em>
For your first exercise you'll enumerate the number's positions fromright to lef begining with 0:
a. F F
position 1 0
Now you'll multiply your hexadecimal number (using the decimal equivalent for your letters) for the base (16) elevated to the number of the position:
Finally, you'll add your results:
240+15=255
FF=255
b. F 0 A 2
position 3 2 1 0
F0A2=61602
c. F 1 0 0
position 3 2 1 0
0F100=61696
d. 1 0 0
position 2 1 0
100=256
I hope you find this information useful! Good luck!
The maximum size of a message queue is 16384 bytes for Linux. For IBM WebSphere MQ. this value is 4 MB.
<h3>What is the message queue?</h3>
The size of the message queue refers to the size (in bytes) that a message may have for a given operative system.
For example, the maximum value for IBM WebSphere MQ has been configured in four megabytes (4 MB).
In this case, when the message is higher than the set size (here 4 MB), then this message is returned.
Learn more about IBM here:
brainly.com/question/896257
Answer:
sqrt(area)
Explanation:
- Here sqrt is a short form of square root.
- area is a variable name having he area of square.
- When the function is called, it will give the square root of the value stored in variable area.
As we have to find the length of the diagonal, we must knew that as all sides of the square are same in length so are the diagonals. This means that each of the four sides of the square and it diagonals are equal in length.
So a square has: length=breadth=diagonal
As Area= length*breadth
√area = length (as length = diagonal length)
So √area = diagonal length
Answer:
import regex as re
def in_parentheses(a_string):
regeX = re.compile(".*?\((.*?)\)")
result = re.findall(regeX, a_string)
return str(result).replace("[","").replace("]","")
print("test 1: "+in_parentheses("Open ( only"))
print("test 2: "+in_parentheses("This is a sentence (words!)."))
