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Marysya12 [62]
2 years ago
13

The points a b c and d lie on a straight line ab:bd = 1:4

Computers and Technology
1 answer:
pochemuha2 years ago
3 0

The points a b c and d lie on a straight line ab:bd = 1:4 are A line that extends to infinity on both sides and has no curves is called a straight line.AB:BC=3:4.

<h3>What do you call a straight line?  </h3>

A line is simply an object in geometry denoted as an object with no width that extends on both sides. A straight line is just a line with no curves.

  • AC=AB+BC=3+4=7;  AC:CD=2:1, i.e. AC=2;   because we get 2 different lengths for AC, we change the given ratio AC:CD to an equivalent one with AC=7 .
  • As follows: AC:CD = 2 : 1 = 7 : 3.5 (multiply both sides by 3.5 )   Now we have AC:CD = 7 : 3.5 and AD = AC+CD= 7+3.5 = 10.5,, and the answer is: the ratio  BC:AD = 4:10.5.

Read more about the straight line:

brainly.com/question/3493733

#SPJ1

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Create a class, using separate files, named DynamicGrades. (2 points) This class has three data members: an int that represents
Alex

Answer:

See explaination

Explanation:

#include <iostream>

using namespace std;

//DynamicGrades.h

class DynamicGrades

{

public:

DynamicGrades(int size);

~DynamicGrades();

void mutate(int studentId, int index, int grade);

int getGrade(int studentId, int index);

private:

int m_studentId;

int m_noofGrades;

int* m_dynamicArr;

};

//DynamicGrades.cpp

#include "DynamicGrades.h"

DynamicGrades::DynamicGrades(int size)

{

m_noofGrades = size;

m_dynamicArr = new int[m_noofGrades] {0};

}

DynamicGrades::~DynamicGrades()

{

if(nullptr != m_dynamicArr)

delete[] m_dynamicArr;

}

void DynamicGrades::mutate(int studentId, int index, int grade)

{

m_studentId = studentId;

if (index < m_noofGrades)

m_dynamicArr[index] = grade;

}

int DynamicGrades::getGrade(int studentId, int index)

{

if (index >= m_noofGrades)

return -1;

return m_dynamicArr[index];

}

//Main.cpp

#include "DynamicGrades.h"

int main()

{

DynamicGrades* grade = new DynamicGrades(5);

DynamicGrades grade2(10);

for (int i = 0;i < 5;++i)

{

grade->mutate(2, i, i + 1);

}

for (int i = 0; i < 10; i++)

{

grade2.mutate(3, i, i + 1);

}

cout << "Grades are " << endl;

for (int i = 0;i < 5;++i)

{

cout << grade->getGrade(2, i) <<" ";

}

cout << endl;

for (int i = 0; i < 10; i++)

{

cout << grade2.getGrade(3, i) << " ";

}

}

3 0
4 years ago
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Juliette [100K]

Answer:

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Explanation:

According to my research on information technology, I can say that based on the information provided within the question if this happens then we can say that the computer has attained intelligence. This is because this is a test developed by Alan Turing in 1950, in order to observe a machine's ability to exhibit intelligent behavior equal to, or indistinguishable from, that of a human.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

5 0
3 years ago
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3 0
3 years ago
Read 2 more answers
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Vadim26 [7]

Answer:

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Explanation:

3 0
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yan [13]

Answer:

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