Write an equation of the line that is parallel to 2x + 4y = 6 and passes through the point (6, 4).

Mathematics

1 answer:

notsponge [240]3 years ago

3 0

Answer:

Step-by-step explanation:

Here's a completely valid trick for finding the equation of this new line:

Start with the given 2x + 4y = 6. Replace that '6' with 'C.' We need to find C. To do this, replace x with 6 and y with 4 and calculate C:

2(6) + 4(4) = C, or 12 + 16 = C. Thus, C = 28, and the desired equation is

2x + 4y = 28, or (in simplified form) x + 2y = 14

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Masja [62]

Answer:

The second one; x²+7x+12

Step-by-step explanation:

So, since the beginning lengths of the square is x and x, the area of the square is x².

But then, you add 3 to one length, so that side is now (x+3), and then you add 4 to the width, so that is now (x+4).

Finally, you would multiply them together to get the equation you would use to find the new area.

For this, you would cross-multiply everything together; the x in the length by the x in the width, the x in the length by the 4 in the width, the 3 in the length by the x in the width, and then the 3 in the length by the 4 in the width. Now, all you have to do is add all of these together to get your answer.

Here's the work:

$(x+3)(x+4)\\x^{2}+3x+4x+12\\x^{2}+7x+12$