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3 years ago

Given that 3(x-c)=2x+5 where c is an integer, shoe that x cannot be a multiple of 6

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

7 0

Answer:

The explanation in the procedure

Step-by-step explanation:

we have

$3(x-c)=2x+5$

solve for c

$3x-3c=2x+5$

$3c=3x-2x-5$

$3c=x-5$

$c=(x-5)/3$

For $x=6$ -----> Find the value of c

$c=(6-5)/3=1/3$ ------> is not an integer

therefore

x cannot be a multiple of 6

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Answer:

Student Hours worked

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Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

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$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

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$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

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Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

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Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

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