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den301095 [7]
3 years ago
10

What is the vertex of the quadratic function f(x)=(x-6)(x+2)

Mathematics
1 answer:
Hunter-Best [27]3 years ago
6 0
The vertex to this quadratic equation is 2

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Can someone help me with this problem pleasee
Nikitich [7]

Answer:

v=8

Step-by-step explanation:

Let's solve your equation step-by-step.

16v−9v=56

Step 1: Simplify both sides of the equation.

16v−9v=56

16v+−9v=56

(16v+−9v)=56(Combine Like Terms)

7v=56

7v=56

Step 2: Divide both sides by 7.

7v

7

=

56

7

v=8

hope this helps!

6 0
3 years ago
Read 2 more answers
A spring has a natural length of 7 m. If a 4-N force is required to keep it stretched to a length of 11 m, how much work W is re
bezimeni [28]

Answer:

18 J is the work required to stretch a spring from 7 m to 13 m.

Step-by-step explanation:

The work done is defined to be the product of the force F and the distance d  that the object moves:

W=Fd

If F is measured in newtons and d<em> </em>in meters, then the unit for is a newton-meter, which is called a joule (J).

This definition work as long as the force is constant, but if the force is variable like in this case, we have that the work done is given by

W=\int\limits^b_a {f(x)} \, dx

Hooke’s Law states that the force required to maintain a spring stretched x    units beyond its natural length is proportional to

f(x)=kx

where k is a positive constant (called the spring constant).

To find how much work W is required to stretch it from 7 m to 13 m you must:

Step 1: Find the spring constant

We know that the spring has a natural length of 7 m and a 4 N force is required to keep it stretched to a length of 11 m. So, applying Hooke’s Law

4=k(11-7)\\\\\frac{k\left(11-7\right)}{4}=\frac{4}{4}\\\\k=1

Thus F=x

Step 2: Find the the work done in stretching the spring from 7 m to 13 m.

Recall that the natural length is 7 m, so when we stretch the spring from 7 m to 13 m, we are stretching it by 6 m beyond its natural length.

Work needed to stretch it by 6 m beyond its natural length

W=\int\limits^6_0 {x} \, dx \\\\\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1\\\\\left[\frac{x^{1+1}}{1+1}\right]^6_0\\\\\left[\frac{x^2}{2}\right]^6_0=18

18 J is the work required to stretch a spring from 7 m to 13 m.

5 0
3 years ago
WILL GIVE BRAINLIEST
galina1969 [7]
I used substitution
The answer is a

3 0
3 years ago
!!! CAN SOMEONE HELP !!! (PLEASE ILL GIVE BRAINLIST)
vladimir1956 [14]

Answer:

120 minutes

Step-by-step explanation:

the total bill was $58 so we have to subtract the $40 monthly bill part to find how much extra money she paid because her call was over 200 minutes

58-40=18

Then divide the $18 by $0.15 since the $18 is the total amount of each time she was charged $0.15 for going 1 minute over 200 minutes

18÷0.15 = 120

120 is te Amount Of minutes she went over her 200 minute limit

6 0
2 years ago
Read 2 more answers
Sam spends $13.50 on baseball cards. The tax is 6%. What is his total cost?
Alexandra [31]

Answer:

13.50+0.81= $14.31

Step-by-step explanation:

Hope this helps!

5 0
3 years ago
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