ANSWER:
- x – 3y = 2 ...(1)
- 2x – 6y = 6 ...(2)
On solving eq(1), we get
Plug the value of x in eq(2)
- 2x – 6(x - 2/3) = 6
- 2x – 2(x – 2) = 6
- 2x – 2x + 4 = 6
- 0 = 6 – 4
- 0 ≠ 2
So, given system of equations is not correct.
Answer:
Zero Solutions
Step-by-step explanation:
3x+3-5=3x-2
3x-3x= -2+5
0= 3
0 does not equal 3, so zero solutions.
Cone=cup:
V=124<span>cm^3.
h=12cm
V=Bh
P=r</span>^2π+rsπ:
B=r^2π
B=V/h=124/12=10,3cm^2
r^2=B/π
r=√(B/π)=1,81 cm
S=√(r^2+h^2)=√(12^2+1.81^2)=√(144+3,28)=12,13 cm
P=r^2π+rSπ=3,28*3,14+1,81*12,13*3,14=10,29+68,93=79,22 cm^2
This question is essentially telling you to move the point (5, -2) over three units, and up four units. That means subtract three units from the x-coordinate and add four units to the y-coordinate. So (5 - 3, -2 + 4) --> (2, 2). The coordinates for the new point are (2, 2).