Question

Triangle ABC has vertices A(0, 6) , B(−8, −2) , and C(8, −2) . A dilation with a scale factor of 12 and center at the origin is applied to this triangle. What are the coordinates of B′ in the dilated image? Enter your answer by filling in the boxes. B′ has a coordinate pair of ( , )

Answer 1

Answer:

$B' = (-96,-24)$

Step-by-step explanation:

Given

$A(0,6)$

$B(-8,-2)$

$C(8,-2)$

Required

Determine the coordinates of B' if dilated by a scale factor of 12

The new coordinates of a dilated coordinates can be calculated using the following formula;

New Coordinates = Old Coordinates * Scale Factor

So;

$B' = B * 12$

Substitute (-8,-2) for B

$B' = (-8,-2) * 12$

Open Bracket

$B' = (-8 * 12,-2 * 12)$

$B' = (-96,-24)$

Hence the coordinates of B' is $B' = (-96,-24)$