Answer:
its 36 gallons
Step-by-step explanation:
Option A
-x + 6y = 42 is the standard form
<u>Solution:</u>
Given that we have to write
in standard form
The standard form of an equation is Ax + By = C
In this kind of equation, x and y are variables and A, B, and C are integers
Given equation is:

Let us convert the above equation into standard form


Make the denominator same in R.H.S

Solve the above equation


Move 6 from R.H.S to L.H.S

Bring all the terms to one side, leaving only constant on R.H.S

The above equation is of form Ax + By = C
Thus option A is correct
The answer for that would be 2 raise to 5. solution:
2 ³ x 2 raise to 6 = 2 raise to 9
thus, you have now,
2 raise to 9 over 2 raise to 4
subtracting 4 from 9
the Answer is 2 raise to 5
Answer:
AC = 10
Step-by-step explanation:
Two tangents drawn to a circle from the same exterior point are congruent.
AC = AB
Since AB = 10, then
AC = 10
Answer:
When reading decimal numbers, read the whole number part as normal, use "and" to represent the decimal point and continue reading the number as normal, but end with the last place value.
For example: how do you read 36.57 --> thirty-six and fifty-sevens hundredths
When writing decimals it is like reading them. You write the whole part as normal, and write a decimal to represent where you would say "and". Continue writing the number.
For example: Write eighty-five and sixty-four hundredths --> 85.64
Step-by-step explanation: