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velikii [3]
3 years ago
13

Round 78482 to the nearest thousand

Mathematics
1 answer:
shtirl [24]3 years ago
6 0

Answer:

78,000

Explanation:

8,000 is in the thousands place, the 4 in the hundreds place is too low to round it up to 9,000, so it gets rounded down to 78,000.

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Scott ran 11 kilometers in nine days. One mile is approximately 1.6 kilometers. About how many miles did Scott run?
natita [175]

Scott run 6.875 miles in nine days.

Step-by-step explanation:

Given,

Distance covered by Scott = 11 kilometer

1.6 kilometer = 1 mile

We will find the unit rate in terms of kilometer;

1 kilometer = \frac{1}{1.6}\ miles

11 kilometers = 11*unit rate of kilometer

11 kilometers = 11*\frac{1}{1.6}

11 kilometers = 6.875 miles

Scott run 6.875 miles in nine days.

Keywords: unit rate, multiplication

Learn more about multiplication at:

  • brainly.com/question/12041380
  • brainly.com/question/120752

#LearnwithBrainly

3 0
3 years ago
Find the 11th term of the arithmetic sequence an=<br> 24 – 7(n - 2)<br> 2115
sweet [91]

Answer:

Let's simplify

24−7(n−2)(2115)

Step-by-step explanation:

step-by-step.

=−14805n+29634

I hope my answer helped

7 0
2 years ago
Please prove. hurry pls
scoray [572]
Where is the image at?
6 0
3 years ago
Suppose a random variable x is best described by a uniform probability distribution with range 22 to 55. Find the value of a tha
const2013 [10]

Answer:

(a) The value of <em>a</em> is 53.35.

(b) The value of <em>a</em> is 38.17.

(c) The value of <em>a</em> is 26.95.

(d) The value of <em>a</em> is 25.63.

(e) The value of <em>a</em> is 12.06.

Step-by-step explanation:

The probability density function of <em>X</em> is:

f_{X}(x)=\frac{1}{55-22}=\frac{1}{33}

Here, 22 < X < 55.

(a)

Compute the value of <em>a</em> as follows:

P(X\leq a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.95\times 33=[x]^{a}_{22}\\\\31.35=a-22\\\\a=31.35+22\\\\a=53.35

Thus, the value of <em>a</em> is 53.35.

(b)

Compute the value of <em>a</em> as follows:

P(X< a)=\int\limits^{a}_{22} {\frac{1}{33}} \, dx \\\\0.95=\frac{1}{33}\cdot \int\limits^{a}_{22} {1} \, dx \\\\0.49\times 33=[x]^{a}_{22}\\\\16.17=a-22\\\\a=16.17+22\\\\a=38.17

Thus, the value of <em>a</em> is 38.17.

(c)

Compute the value of <em>a</em> as follows:

P(X\geq  a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.85=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.85\times 33=[x]^{55}_{a}\\\\28.05=55-a\\\\a=55-28.05\\\\a=26.95

Thus, the value of <em>a</em> is 26.95.

(d)

Compute the value of <em>a</em> as follows:

P(X\geq  a)=\int\limits^{55}_{a} {\frac{1}{33}} \, dx \\\\0.89=\frac{1}{33}\cdot \int\limits^{55}_{a} {1} \, dx \\\\0.89\times 33=[x]^{55}_{a}\\\\29.37=55-a\\\\a=55-29.37\\\\a=25.63

Thus, the value of <em>a</em> is 25.63.

(e)

Compute the value of <em>a</em> as follows:

P(1.83\leq X\leq  a)=\int\limits^{a}_{1.83} {\frac{1}{33}} \, dx \\\\0.31=\frac{1}{33}\cdot \int\limits^{a}_{1.83} {1} \, dx \\\\0.31\times 33=[x]^{a}_{1.83}\\\\10.23=a-1.83\\\\a=10.23+1.83\\\\a=12.06

Thus, the value of <em>a</em> is 12.06.

7 0
3 years ago
Complete the solution of the equation. Find the value of y when x equals -2. -4x+8y=-24 ​
zepelin [54]

Answer:y=-4

Step-by-step explanation:

Multiply -4 by -2 you get positive 8 rewrite the equation subtract 8 from both sides that leaves you with 8y=-32 your final step is to divide both sides 8 that leaves you with -4 which is the answer.

5 0
3 years ago
Read 2 more answers
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