Question

Help me answer this question please

Answer 1

Answer:

The answer is C.

Step-by-step explanation:

Just go to Desmos.com and plug it in.

Answer 2

For this case we have:

Let k> 0:

To graph$y = f (x) + k,$ the graph k units is moved up.

To graph $y = f (x) -k$, the graph moves k units down.

Let h> 0:

To graph $y = f (x-h)$, the graph moves h units to the right.

To graph $y = f (x + h),$ the graph moves h units to the left.

So, we have:

$y = f (x) = \sqrt [3] {x}$

Shifted 1 unit down and 4 to the left means:

$k = 1\\h = 4$

$y = f (x) = \sqrt [3] {x + 4} -1$

Answer:

Option D