2 years ago

5. A race course is 99 meters long. There are trees

Mathematics

2 answers:

Ivanshal [37]2 years ago

7 0

Answer:

Step-by-step explanation:

99 minus 38

Svet_ta [14]2 years ago

5 0

Answer:

61 meters

Step-by-step explanation:

To find this answer, you need to subtract the length with trees from the total length of the course. With this information, you get an equation that looks something like x + 38 = 99, with x being the length of the course without trees.

Subtract 38 from both sides:

x + 38 = 99

- 38 - 38

x = 99 - 38

Simplify:

x = 61

You might be interested in

-23/6 - 7/3=? explain please

vlabodo [156]

Answer:

37/6

Step-by-step explanation:

-23/6 - 7/3

= -23/6 - 14/6 just make both have the same denominator (2x the 3 to make 6 and do same with numerator)

= 37/6 or 6 1/6

8 0

2 years ago

Read 2 more answers

Please help me with these three questions asap, thank you

Y_Kistochka [10]

Answer:

Coef=6

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

If f(x)= 15x+7x and g(x)= x^2-5x, find (f+g)(x)

cupoosta [38]

Answer:

(f+g)(x) = x^2 +10x +7

Step-by-step explanation:

(f+g)(x) = f(x) +g(x) = (15x +7) +(x^2 -5x)

= x^2 +x(15 -5) +7

= x^2 +10x +7

7 0

3 years ago

Andre adds 0.25 milliters of dye to 12.3 of water how many milliters does the mixture contain

Tasya [4]

Jttjrjtjjtjtjttjhfjduudud

4 0

3 years ago

Write the first 4 terms for <br>f (1) = 3, f (n) = [f(n-1)]

Alexxx [7]

$f(1)=3\\\\f(n)=[f(n-1)]\\\\f(2)=[f(2-1)]=[f(1)]=[3]=3\\\\f(3)=[f(3-1)]=[f(2)]=[3]=3\\\\f(4)=[f(4-1)]=[f(3)]=[3]=3\\\\f(5)=[f(5-1)]=[f(4)]=[3]=3$

4 0

3 years ago