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Talja [164]
2 years ago
9

Group Radii of Tomatoes (centimeters)

Mathematics
1 answer:
denis23 [38]2 years ago
5 0

Answer: Option 'B' is correct.

Step-by-step explanation:

since we have given that

Group radii of fertilized tomatoes is given by

0.8, 1.1, 0.9, 0.8, 1.0, 1.2, 0.9, 1.1, 1.0, 1.2

Group radii of unfertilized tomatoes is given by

1.4, 1.6, 1.3, 1.5, 1.1, 1.5, 1.6, 1.2

So, we will first find the mean of both the group i.e.

Mean radii of fertilized tomatoes is given by

=\frac{0.8+1.1+0.9+0.8+1.0+1.2+0.9+1.1+1.0+1.2}{10}\\\\=1

Similarly,

Mean radii of unfertilized tomatoes is given by

\frac{1.4+1.6+1.3+1.5+1.1+1.5+1.6+1.2}{8}\\\\=\frac{11.2}{8}\\\\=1.4

So, the difference between the mean radii of fertilized and unfertilized tomatoes will be

1.4-1=0.4\ cm

Hence, Option 'B' is correct.

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3 years ago
Solve h = −16t2 + 36t + 4.
kvasek [131]
I can do each of the things I asked above.
So, let's change this into vertex form:
h=-16t^2+36t+4
h=(-16t^2+36t)+4
h=-16(t^2-2.25t)+4
h=-16(t^2-2.25t+1.27-1.27)+4
h=-16(t^2-2.25t+1.27)+20.32+4
h=-16(t-1.125)^2+24.32
The vertex is at (1.125,24.32)
<span>Answers may vary due to rounding

</span>Factored Form:
h = -16t^2 + 36t + 4
h = -4\left(4t^2-9t-1\right)

Quadratic Formula:
x =  \frac{-b +/- \sqrt{b^2-4(a)(c)}}{2a}
<span>h = -16t^2 + 36t + 4
</span>a = -16 b = 36 c = 4
h = \frac{-(36) +/- \sqrt{(36)^2-4(-16)(4)}}{2(-16)}
h = \frac{-36 +/- \sqrt{1552}}{-32}
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5 0
2 years ago
Five students visiting the student health center for a free dental examination during National Dental Hygiene Month were asked h
kirza4 [7]

Answer:

95% confidence interval for the mean number of months is between a lower limit of 6.67 months and an upper limit of 25.73 months.

Step-by-step explanation:

Confidence interval is given as mean +/- margin of error (E)

Data: 5, 15, 12, 22, 27

mean = (5+15+12+22+27)/5 = 81/5 = 16.2 months

sd = sqrt[((5-16.2)^2 + (15-16.2)^2 + (12-16.2)^2 + (22-16.2)^2 + (27-16.2)^2) ÷ 5] = sqrt(58.96) = 7.68 months

n = 5

degree of freedom = n-1 = 5-1 = 4

confidence level (C) = 95% = 0.95

significance level = 1 - C = 1 - 0.95 = 0.05 = 5%

critical value (t) corresponding to 4 degrees of freedom and 5% significance level is 2.776

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Lower limit of mean = mean - E = 16.2 - 9.53 = 6.67 months

Upper limit of mean = mean + E = 16.2 + 9.53 = 25.73 months

95% confidence interval is (6.67, 25.73)

3 0
2 years ago
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