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k0ka [10]
4 years ago
14

You are given two true-breeding groups of rabbits. the first group has white hair. the second group has black hair. the second g

roup has black hair. when you perform a cross of these two groups to obtain an f1 generation, you see that all of your rabbits have grey hair. what would you expect of the f2 generation?
Biology
1 answer:
earnstyle [38]4 years ago
7 0
Well what is expected is a mode of inheritance that is incomplete dominance as the f1 offspring organisms are all heterozygous and that would mean that they would be intermediates of the 2 pure breeding parents, and have their own phenotype.

If you cross 2 f1 generation offspring

The resulting phenotype would be 1 white rabbit : 1 black rabbit : 2 grey rabbits.
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120 white individuals

30 yellow individuals

10 green individuals  

Explanation:

Available data:

  • Dominant epistasis: Phenotypic frequencies 12:3:1
  • W allele codes for a dominant white phenotype
  • w allele codes for a colored squash
  • Y allele codes for a dominant yellow phenotype
  • y allele codes for a recessive green phenotype
  • W allele will always mask the phenotype produced by Y or y alleles
  • 160 offspring

Dihybrid Cross

Parental)   WwYy      x      WwYy

Gametes) WY   Wy    wY    wy

                 WY   Wy    wY    wy

Punnet Square)

                            WY         Wy        wY       wy

               WY     WWYY   WWYy   WwYY  WwYy

               Wy      WWYy   WWyy    WwYy  Wwyy

               wY      WwYY   WwYy    wwYY  wwYy

               wy       WwYy   Wwyy    wwYy  wwyy

F1 Phenotypic Frequency)

White phenotype: 12/16 = 120 individuals

Yellow phenotype: 3/16 = 30 individuals

Green Phenotype: 1/16 = 10 individuals

To know how many offspring are expected to have the white, yellow, and green phenotypes, you can perform a three simple rule. This is:

16 ------- 160 offspring

12 White ------- X = 120 offspring

3 Yellow ------- X= 30 offspring

1 Green --------X = 10 offspring              

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