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klemol [59]
3 years ago
11

William is competing in the shot put event at a track meet. The quadratic expression that models the vertical height of the shot

put from the ground, in feet, over the horizontal distance traveled, in feet, X, is given below.
-2x^2 + 3x + 5
A.the initial height from which the shot was thrown
B.the maximum height of the shot
C.the time it takes for the shot to reach the ground
D. The horizontal distance covered by the shot.

Mathematics
2 answers:
iVinArrow [24]3 years ago
6 0

Answer:

A. 5 units

B. 6.125 units

C. Can't be determined

D. 2.5 units

Step-by-step explanation:

A. initial height is determined by the y-intercept which is 5

B. Maximum height is given by x-coordinate of vertex of the parabola i.e. 6.125

C. As the graph doesn't give any relation between time and height so the time can't be determined

D. horizontal distance is measured by the distanced traveled along x-axis.


KATRIN_1 [288]3 years ago
5 0
If you graph the equation, you will see the vertex is (0.75, 6.125), the y-intercept is (0, 5) and the x-intercept is (2.5, 0). These key points answer the questions below.

A. It starts at 5 feet (y-intercept)
B. The max height is 6.125 feet (vertex)
C. Cannot be found (the graph is about height and distance, not time)
D. If lands 2.5 feet from the start (x-intercept)
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Urgent help needed algebra 2
dlinn [17]

The missing values are shown in the attached picture, and 41 degrees F = 5 degrees C.

<h3>What is unit conversion?</h3>

It is defined as the conversion from one quantity unit to another quantity unit followed by the process of division, and multiplication by a conversion factor.

We have:

\rm F = \dfrac{9}{5}C + 32

Make subject C and solve:

\rm \dfrac{5}{9}(F-32) = \dfrac{5}{9}\times\dfrac{9}{5}C

\rm \dfrac{5}{9}(F-32) = C

Plug F = 41

\rm \dfrac{5}{9}(41-32) = C

\rm \dfrac{5}{9}(9) = C

41 degrees F = 5 degrees C

Thus, the missing values are shown in the attached picture, and 41 degrees F = 5 degrees C.

Learn more about the unit conversion here:

brainly.com/question/14350438

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3 0
2 years ago
If 1m is 100cm, then 250cm equivalent of 2.5m<br> if 1kg is 1.00g then 3kg is 2.500g
Viefleur [7K]

Answer:

I Kg = 1000 g

3 Kg = 3000 Kg

Step-by-step explanation:

Kg - Hg - Dag - g

1 Kg - 10 Hg - 100 Dag - 1000 g

So, 1 Kg = 1000 g

3 Kg = 3(1000)g = 3000 g

3 0
3 years ago
Erin had $6,191.50 in a savings account with simple interest. She had opened the account with $6,100 just six months earlier. Wh
NNADVOKAT [17]

Answer:

  3%

Step-by-step explanation:

Erin earned 6191.50 -6100 = 91.50 in interest in 6 months on a 6100 principal. Then the annual interest rate is ...

  I = Prt

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The interest rate was 3%.

6 0
3 years ago
Read 2 more answers
PLEASE EXPLAIN THIS 6th GRADE MATH
8090 [49]

Answer:

b = l\times w to guarantee that both formulas are the same.

Step-by-step explanation:

Dimensionally speaking, the volume is the cube of length. By direct comparison, we find that l,w,h have length units, whereas b have area unit, that is, the square of length.

Hence, b = l\times w to guarantee that both formulas are the same.

8 0
3 years ago
What is the average rate of change of f over the interval -1 on a separate sheet of paper and upload the work as a photo. Show a
Anarel [89]

Answer:

Average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

Step-by-step explanation:

We need to find average rate of change of f over the interval -1 < x < 1

The function given is: f(x)= x^2-x-1

The formula used to find average rate of change is:

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}

We have, a = -1 and b = 1

Finding f(b) when b=1

f(x)=x^2-x-1\\f(1)=(1)^2-(1)-1\\f(1)=1-1-1\\f(1)=-1

Now, finding f(a), when a= -1

f(x)=x^2-x-1\\f(-1)=(-1)^2-(-1)-1\\f(1)=1+1-1\\f(-1)=2-1\\f(-1)=1

Now, putting values and finding average rate of change

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So, average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

4 0
3 years ago
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