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4 years ago

Please help with this question !!!!

Mathematics

2 answers:

makkiz [27]4 years ago

7 0

$\bf \begin{cases}
f(x)=6x\\
g(x)=4x+1
\end{cases}\qquad (f\circ g)(x)\iff f(\quad g(x)\quad )
\\\\\\
\textit{that is}\implies
\begin{cases}
f(\boxed{x})=6\boxed{x}
\\\\
f(\boxed{g(x)})=6\boxed{g(x)}\\
--------------\\
g(x)=4x+1\qquad thus\\
--------------\\
f(\boxed{g(x)})=6(\boxed{4x+1})\iff (f\circ g)(x)
\end{cases}$

distribute and simplify if needed, see what you get

julsineya [31]4 years ago

7 0

I think it is A because if you do the math 4x+ 1 = 1 and A is the same hope that helps

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