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3 years ago

7

The ferry between the island and the mainland makes one round trip a day. On Monday the ferry carried 83 people to the island an

d returned 114 people to the mainland. Compare the population of the island at the beginning of the day to the population after the ferry returned.

1 answer:

mylen [45]3 years ago

5 0

You can subtract 114-83 which equals 31

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just olya [345]

Answer:

discount = 290 × <u>1</u>

4

= 72.50

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290.00

<u>72.50</u> -

217.50

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3 years ago

Use ABC to find the value of cos a. 24/7 7/24 7/25 24/25

ExtremeBDS [4]

Answer:

$\frac{24}{25}$

Step-by-step explanation:

using the cosine ratio;

$\cos(\theta)= \frac{adjacent}{hypotenuse}$

From the question, the side of the right angle triangle that is adjacent to the measured <a,(i.e BAC) is AC=24 and the hypotenuse is AB=25

This implies that,

$cos(a)= \frac{24}{25}$

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3 years ago

Can anyone help me? is it a b c or d

Nataly_w [17]

Answer: choice a

Step-by-step explanation:

The Triangle Inequality Theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side. Note: This rule must be satisfied for all 3 conditions of the sides.

so it has to be in between 9 and 5

7+2=9

2+x>7

--> x>5

however, it can't be 5 or 9

Hope this helps! <3

5 0

3 years ago

I WILL GIVE BRAINLIEST

shusha [124]

Answer:

x = -3

Step-by-step explanation:

$y\geq -\frac{2}{3} x-3\\
y\leq 3x+8$

$-\frac{2}{3} x-3=3x+8$

Add 2/3 x to both sides: $-3=\frac{11}{3}x+8$

Subtract 8 from both sides: $-11=\frac{11}{3}x$

Multiply both sides by 3: $-33=11x$

Divide both sides by 11: $x=-3$

Therefore, point of intersection between both lines is at point (-3, -1)

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2 years ago

You decide to enter in a rowing competition. To train, you go to the boat house and begin rolling down stream. You row for the s

fredd [130]

Answer:

Time spent rowing down stream $=100\ seconds$

Speed of boat in still water $=14\ ms^{-1}$

Step-by-step explanation:

Let speed of boat in still water be $= x\ ms^{-1}$

Speed of current $= 10\ ms^{-1}$

Speed of boat down stream = $\textrm{Speed of boat in still water +Speed of current}= (x+10)\ ms^{-1}$

Distance rowed down stream = 2400 m

Time spent rowing down stream = $\frac{Distance}{Speed}=\frac{2400}{x+10}\ s$ = $\frac{Distance}{Speed}=\frac{2400}{x+10}\ s$

Speed of boat up stream = $\textrm{Speed of boat in still water -Speed of current}= (x-10)\ ms^{-1}$

Distance rowed up stream = $\frac{1}{6} \textrm{ of distance rowed downstream}=\frac{1}{6}\times 2400 = 400\ m$

Time spent rowing up stream = $\frac{Distance}{Speed}=\frac{400}{x-10}\ s$

We know that,

$\textrm{Time spent rowing down stream =Time spent rowing up stream}$

So,

$\frac{2400}{x+10}=\frac{400}{x-10}$

Cross multiplying

$2400(x-10)=400(x+10)$

Dividing both sides by $400$

$\frac{2400(x-10)}{400}=\frac{400(x+10)}{400}$

$6(x-10)=x+10$

$6x-60=x+10$

Adding 60 to both sides.

$6x-60+60=x+10+60$

$6x=x+70$

Subtracting both sides by $x$

$6x-x=x+70-x$

$5x=70$

Dividing both sides by 5.

$\frac{5x}{5}=\frac{70}{5}$

∴ $x=14$

Speed of boat in still water $=14\ ms^-1$

Time spent rowing down stream = $\frac{2400}{14+10}=\frac{2400}{24}=100\ s$

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2 years ago