Mole percent of O2 = 10% = 0.1 moles
Mole percent of N2 = 10% = 0.1 moles
Mole percent of He = 80% = 0.8 moles
Molar Mass of O2 = (2 x 16) x 0.1 = 3.2
Molar Mass of N2 = (2 x 14) x 0.1 = 2.8
Molar Mass of He = 4 x 0.8 = 3.2
1. Molar Mass of the mixture = 3.2 + 2.8 + 3.2 = 9.2 grams
2. Since at constant volume density is proportional to mass, so the ratio of
mass will be the ratio of density.
Ratio = Molar Mass of the mixture / Molar Mass of O2 = 9.2 / 32 = 0.2875
.50,mol
sodium acetate (NaCH3CO2) should be added to maximize the buffering
effect.
<span>
</span><span>A </span>buffering effect<span> is a process in which a psychosocial resource
reduces the impact of life stress on psychological well-being. Having such a
resource contributes to adjustment because persons are less affected by
negative life events.</span>
Cells are so little, so they can maximize their ratio of surface area to volume. Smaller cells have a higher ratio which allow more molecules and ions move across the cell membrane per unit of cytoplasmic volume. Cells are so small because they need to be able to get the nutrients in and the waste out quickly.
Hello!
For this problem, we will be applying <em>Charles' Law</em>:
V1/T1 = V2/T2
Now that we have the formula, let's convert the temperature to Kelvin.
27 + 273 = 300K
Let's plug everything in now!
10/300 = 12.0/x
Simplified:
1/30 = 12.0/x
Cross-multiply:
1x = 30*12.0
<u>x = 360</u>
<em>Check!</em>
10/300 = 12/360
300*12 = 360*10
3600 = 3600
Therefore, you would have to heat the gas at a temperature of 360K in order to raise the volume to 12.0L.
The answer is A, biogeochemical cycles.
