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Sindrei [870]
3 years ago
13

How do a single, double, and triple covalent bonds form?

Chemistry
1 answer:
satela [25.4K]3 years ago
6 0

Explanation:

Single covalent bonds

When an atom needs 1 electron to attain noble gas configuration they share rhe atoms in order to gain this ex ; H2 molecule

double covalent; O2 molecule

triple covalent; N2 molecule

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COCl2(g) decomposes according to the equation above. When pure COCl2(g) is injected into a rigid, previously evacuated flask at
mestny [16]

<u>Answer:</u> The value of K_p for the reaction at 690 K is 0.05

<u>Explanation:</u>

We are given:

Initial pressure of COCl_2 = 1.0 atm

Total pressure at equilibrium = 1.2 atm

The chemical equation for the decomposition of phosgene follows:

                  COCl_2(g)\rightleftharpoons CO(g)+Cl_2(g)

Initial:            1                    -         -

At eqllm:       1-x                 x        x

We are given:

Total pressure at equilibrium = [(1 - x) + x+ x]

So, the equation becomes:

[(1 - x) + x+ x]=1.2\\\\x=0.2atm

The expression for K_p for above equation follows:

K_p=\frac{p_{CO}\times p_{Cl_2}}{p_{COCl_2}}

p_{CO}=0.2atm\\p_{Cl_2}=0.2atm\\p_{COCl_2}=(1-0.2)=0.8atm

Putting values in above equation, we get:

K_p=\frac{0.2\times 0.2}{0.8}\\\\K_p=0.05

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3 years ago
Describe how the mass of the product can be calculated when one reactant is in excess
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On the off chance that one of the reactants is in overabundance yet you don't know which one it is, you have to compute the hypothetical item mass for the both reactants, with a similar item, and whichever has the lower yield is the one you use to precisely depict masses/sums for the condition, since you can't have more than the non-abundance reactant can create.
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rewona [7]
Water has a density of 1 g/cc. If you have 1 cc of water, then the mass it contains would be 1 g. <span>Density is a physical property of a substance that represents the mass of that substance per unit volume. It is a property that can be used to describe a substance. Hope this answers the question. Have a nice day.</span>
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