15. x ≤ -24
x + 19 ≤ -5
x ≤ -24
16. z > -12
3z > -36
z > -12
17. 185 + c > 410; c > 225
18. C.
x - 6 ≥ 1
x ≥ 7
Start by decomposing the number inside the root into primes
Then group the terms into cubes if possible

rewrite the root
![\sqrt[3]{80}=\sqrt[3]{10\cdot2^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B80%7D%3D%5Csqrt%5B3%5D%7B10%5Ccdot2%5E3%7D)
then cancel the terms that are cubes and bring them out of the root
Answer:
E:
Step-by-step explanation:
The equation of circles is
(x-a)²+(y-b)²=r²
Where
Center = (a,b) = (-6,-3) and r = 12
Now
The equation becomes
(x+6)²+(x+3)²=144
Answer:
-3z-11=11z^2
Step-by-step explanation: