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Romashka-Z-Leto [24]
3 years ago
14

Determining Exponential Growth and Decay in Exercise, use the given information to write an exponential equation for y. Does the

function represent exponential growth or exponential decay?
dy/dt = -2/3y, y = 20 when t = 0
Mathematics
1 answer:
scZoUnD [109]3 years ago
8 0

Answer:

y=20e^{-\frac{2}{3}t}

Exponential decay

Step-by-step explanation:

We are given that

\frac{dy}{dt}=-\frac{2}{3}y

y=20 when t=0

\frac{dy}{y}=-\frac{2}{3}dt

Taking integration on both sides then we get

lny=-\frac{2}{3}t+C

Using formula  \int \frac{dx}{x}=lnx,\int dx=x

y=e^{-\frac{2}{3}t+C}

Using formula

lnx=y\implies x=e^y

y=e^C\cdot e^{-\frac{2}{3}t}

e^C=Constant=C

y=Ce^{-\frac{2}{3}t}

Substitute y=20 and t=0

20=C

Substitute the value of C

y=20e^{-\frac{2}{3}t}

When t tends to infinity then

\lim_{t\rightarrow\infty}=\lim_{t\rightarrow\infty}20e^{-\frac{2}{3}t}=0

When time increases then the value of function decrease

Hence, the  function is exponential decay.

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Hey there!

To figure out what "x" means, you can divide the numbers 126 and 14  . . .

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x = 9
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2 years ago
HD Straight line graphs
Taya2010 [7]

Answer:

The equation of the sraight line  3x- y+ 6 =0

Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the gradient of the function

   |gradf| = 3  and point (-1,3)

Given that the slope of the line

 m = 3

The equation of the straight line passing through the point(-1,3) and slope m =3

y -y_{1} = m(x-x_{1} )

y-3 = 3(x-(-1))

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3x +3-y+3=0

3x- y+ 6 =0

<u><em>Final answer:-</em></u>

The equation of the sraight line  3x- y+ 6 =0

<u><em></em></u>

   

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