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Karolina [17]
2 years ago
9

This k12 question i need help

Mathematics
2 answers:
zhannawk [14.2K]2 years ago
8 0

Answer:

Logo = 72

Step-by-step explanation:

The question is not well worded. Which square is used? I will pick the interior one.

s = 6

Area = s^2

Area = 6^2

Area = 36

1 triangle

h = 3cm

base = 6

Area = 1/2 * b * h

Area = 1/2 * 6 * 3

Area = 9

Area of 4 triangles

Area = 4 * 9 = 36

Total area = 36 + 36 = 72

Yuri [45]2 years ago
4 0

Answer: It's 72.

Step-by-step explanation: They deleted my answer <:(

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6. How many 4 digit odd numbers can be formed if no digit can be repeated?
ale4655 [162]
1, 3, 5, 7, 9 are the possible digits

meaning you have 5! possible combinations or 120 combinations
6 0
2 years ago
Which expression is equivalent to the product of p+7/3 and 6/p , where p is not equal to 0?
vichka [17]

Answer:

\frac{(6p+14)}{p}

Step-by-step explanation:

(p+\frac{7}{3})(\frac{6}{p})

Making denominator same in first bracket we get

(\frac{3p+7}{3})(\frac{6}{p})

(\frac{(3p+7)*6}{3*p})

Dividing 6 by 3 we get 2

(\frac{(3p+7)*2}{p})

using distributive law

(\frac{6p+14}{p})\\

Hence this is our answer

8 0
3 years ago
Read 2 more answers
Can somebody prove this mathmatical induction?
Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

\sum \limits_{j=1}^k2^j=2(2^k-1)

3 step:

Check for n=k+1 whether the statement

\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)

is true.

Start with the left side:

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)

According to the 2nd step,

\sum \limits_{j=1}^k2^j=2(2^k-1)

Substitute it into the \ast

\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)

So, you have proved the initial statement

4 0
3 years ago
Please help me understand this! Thanks a bunch if you help!
mariarad [96]
Segment BD equals 12<span />
6 0
3 years ago
Find an equation of the line that satisfies the given conditions. through (−5, −7); perpendicular to the line passing through (−
murzikaleks [220]

Answer:

The equation would be y = 2x + 3

Step-by-step explanation:

In order to solve this, we first need to find the slope of the line between (-2, 5) and (2, 3). In order to do this, we use the slope formula.

m(slope) = (y2 - y1)/(x2 - x1)

m = (3 - 5)/(2 - -2)

m = -2/4

m = -1/2

Now that we have the original line with a slope of -1/2, we can tell a perpendicular line would have a slope of 2. This is because perpendicular lines have opposite and reciprocal slopes. Now we can use that slope and the given point in point-slope form to get the answer. Be sure to solve for y.

y - y1 = m(x - x1)

y + 7 = 2(x + 5)

y + 7 = 2x + 10

y = 2x + 3

7 0
3 years ago
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