All categories

3 years ago

Round 23,879 to the nearest thousand

1 answer:

3 0

23, 879 to the nearest thousand.

The thousand digit is the 3, and we look at the digit after 3, which is 8, since 8 is more than 5, we round up the 3 to 4.

Therefore 23, 879 to the nearest thousand ≈ 24, 000

I hope this explains it.

You might be interested in

I NEED HELP PLSSSSSSSS

AVprozaik [17]

Answer:

X >>>>> Y

–1 >>>> 16

0 >>>>> 8

1 >>>>> 4

2 >>>>> 2

3 >>>>> 1

Step-by-step explanation:

From the question given above,

y = 8 × (½)ˣ

When x = –1, y =?

y = 8 × (½)ˣ

y = 8 × (½)¯¹

y = 8 × 2

y = 16

When x = 1, y =?

y = 8 × (½)ˣ

y = 8 × (½)¹

y = 8 × ½

y = 4

When x = 2, y =?

y = 8 × (½)ˣ

y = 8 × (½)²

y = 8 × ¼

y = 2

When x = 3, y =?

y = 8 × (½)ˣ

y = 8 × (½)³

y = 8 × ⅛

y = 1

SUMMARY:

X >>>>> Y

–1 >>>> 16

0 >>>>> 8

1 >>>>> 4

2 >>>>> 2

3 >>>>> 1

4 0

3 years ago

Find the value of x.

ehidna [41]

Answer:

x = 25

Step-by-step explanation:

We know that the remaining angles add up to 90°, because the right angle (triangles have 180° total.)

2x + 15 + x = 90 | Given

3x + 15 = 90 | Combine x

3x = 75 | Subtract 15

x = 25

4 0

3 years ago

Write a paragraph comparing the two classes' semester grades. Be sure to compare the extremes, the quartiles, the medians, and t

Gnom [1K]

Answer:

Second class have higher marks and greater spread.

Step-by-step explanation:

First box plot represents class first. From the first box plot, we get

$\text{Minimum value }= 53,Q_1=62,Median=80,Q_3=86,\text{Maximum value }= 89$

$Range=Maximum-Minimum=89-53=36$

$IQR=Q_3-Q-1=86-62=24$

Second box plot represents class second. From the second box plot, we get

$\text{Minimum value }= 56,Q_1=62,Median=74,Q_3=89,\text{Maximum value }= 96$

$Range=Maximum-Minimum=96-56=40$

$IQR=Q_3-Q-1=89-62=27$

First class has greater minimum value, first quartile of both classes are same, second class has greater median, first class has greater third quartile and first class has greater maximum value. It means second class have higher marks but class first have less variation.

Second class has greater range and greater inter quartile range. It means data of second class has greater spread.

Therefore, second class have higher marks and greater spread.

3 0

3 years ago

PLEASE HELP ASAP IM GIVING BRAINLIST TO THE BEST ANSWER!

ehidna [41]

Answer:

E. y - 4 = 6(x+2) is the answer

slope:

m = -8-4/-4+2 = 6

Formula:

y - ys1 = m(x - xs1)

hope this helps!

Step-by-step explanation:

4 0

3 years ago

The population of Luis’s city in 2005 was 7400 and the population in 2010 was 9000. Let x represent the number of years since 20

podryga [215]

Answer:

The linear equation is;

y = 320x + 7400

Step-by-step explanation:

Here, we want to write a linear equation that represents the population y at a year since 2005

To write this, we need points

Initially, we have (0,7400)

Since the difference between 2005 and 2010 is 5, the second point will be (5,9000)

Mathematically, we can get the slope as follows;

m = (y2-y1)/(x2-x1) = (9000-7400)/(5-0) = 1,600/5 = 320

The equation of the line can be represented using the general form as;

y = mx + b

where m is 320 and b is unknown

So we have the equation as;

y = 320x + b

we need to get b

To get b, we can use any point

let us use the point (0,7400)

substituting this;

7400 = 320(0) + c

c = 7400

so the equation is;

y = 320x + 7400

4 0

3 years ago