3 years ago

A number is divisible by ______ if the last two digits form a number divisible by four

Mathematics

2 answers:

icang [17]3 years ago

7 0

Answer:

B. 4

Step-by-step explanation:

Whole numbers are divisible by 4 if the number formed by the last two individual digits is evenly divisible by 4.

12345 [234]3 years ago

3 0

Answer:

Step-by-step explanation:

Didn’t i say this in my last post :/ welp since the third digit is 100 and 100 or any multiple of 100 is divisible by 4 you don’t have to worry about the third digit and beyond so the first 2 digits count.

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If cosθ=513, what is sinθ?

Roman55 [17]

The only values a cosine can have are from -1 to 1.

6 0

3 years ago

Simplify the following: 7-3[(n^3+8n)/(-n)+9n^2]

Pachacha [2.7K]

If you would like to simplify 7 - 3[(n^3 + 8n) / (-n) + 9n^2], you can do this using the following steps:

7 - 3[(n^3 + 8n) / (-n) + 9n^2] = 7 - 3[(-n^2 - 8) + 9n^2] = 7 - 3[-n^2 - 8 + 9n^2] = 7 - 3[ - 8 + 8n^2] = 7 - 3[8n^2 - 8] = 7 - 24n^2 + 24 = - 24n^2 + 31

The correct result would be - 24n^2 + 31.

7 0

3 years ago

Please help with this question Only real answers please.

Evgesh-ka [11]

minimum (-2,-2)

hope this will help